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RoseWind [281]
3 years ago
7

A softball has a mass of 0.18 kg. What is the gravitational force on Earth due to the ball, and what is the Earth's resulting ac

celeration? Earth's mass is 6.0 x 1024 kg.​
Physics
1 answer:
alexgriva [62]3 years ago
6 0

Answer:F=1.7802

Explanation:

Since we've been given the mass to be .18kg,we are asked to find the Force of which the formulae is

F=ma where f-force,m-mass and a-acceleration due to gravity

So we can just substitute

F-?.m=.18 and a9.89

F=.18×9.89

F=1.7802N

You might be interested in
Which way will the people on the right move? Why? Plz answer
Scrat [10]
Probably to the right because the force on the left is greater and will therefore overpower the 2N force and push to the right
3 0
3 years ago
Two identical objects in outer space have a head-on collision and stick together. If, before the collision, one had been moving
julia-pushkina [17]

Answer:

1.5 m/s

Explanation:

Momentum is conserved and conservation of momentum is

p₁ + p₂ = p'₁ + p'₂

or

m₁v₁ + m₂v₂ = m₁v'₁  + m₂v'₂

In our problem, after collision v'₁ will be equal to v'₂.

Since objects are identical m₁ = m₂

m(v₁+ v₂) = 2m x v'₁

(2m/s + 1m/s) = 2v'₁

v'₁ = v'₂ = 1.5 m/s

5 0
3 years ago
Two resistors, A and B, are connected in a series circuit with a battery. The resistance of A is twice that of B. Which resistor
IgorC [24]

Answer:

A dissipates more power.

Explanation:

  • In a series circuit, the current is the same at any point in it.
  • The power dissipated in any resistor follows Joule's law, as follows:

        P = I^{2} * R

  • So, for a given current, the power is directly proportional to the resistance of the resistor.
  • In this case, as resistor A has twice the resistance of resistor B, A dissipates twice more power than B.
8 0
3 years ago
What is the net charge of a metal ball if there are 21,749 extra electrons in it?
pickupchik [31]

Answer:

Q=3.47\times 10^{-15}\ C

Explanation:

Given that,

Number of extra electrons, n = 21749

We need to find the net charge on the metal ball. Let Q is the net charge.

We know that the charge on an electron is q=1.6\times 10^{-19}\ C

To find the net charge if there are n number of extra electrons is :

Q = n × q

Q=21749\times 1.6\times 10^{-19}\ C

Q=3.47\times 10^{-15}\ C

So, the net charge on the metal ball is 3.47\times 10^{-15}\ C. Hence, this is the required solution.

6 0
3 years ago
(01.06 MC)
Cerrena [4.2K]

Answer:

c

Explanation:

7 0
3 years ago
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