Answer:
V=I×R
<em>4</em><em>.</em><em>5</em><em> </em><em>=</em><em> </em><em>I×</em><em>9</em>
<em> </em><em> </em><em> </em><em>I</em><em>.</em><em> </em><em>=</em><em> </em><em>4</em><em>.</em><em>5</em><em>/</em><em>9</em>
<em> </em><em> </em><em> </em><em>I</em><em>. </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>
<em>curre</em><em>nt</em><em> </em><em>is</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>
U=0
<span>t=10 </span>
<span>a=9.8m/s/s </span>
<span>v is velocity (the tower must be very high to be able to fall for 10 seconds!!!) </span>
<span>you work out the result now</span>
It's probably because there is no gravity which ballpoint pens need for inkflow to the tip.
Answer:
0.94 m³/s
Explanation:
From the question given above, the following data were obtained:
Air flow (in ft³/min) = 2×10³ ft³/min
Air flow (in m³/s) =.?
Next, we shall convert 2×10³ ft³/min to m³/min. This can be obtained as follow:
35.315 ft³/min = 1 m³/min
Therefore,
2×10³ ft³/min = 2×10³ ft³/min × 1 m³/min / 35.315 ft³/min
2×10³ ft³/min = 56.63 m³/min
Finally, we shall convert 56.63 m³/min to m³/s. This can be obtained as follow:
1 m³/min = 1/60 m³/s
Therefore,
56.63 m³/min = 56.63 m³/min × 1/60 m³/s ÷ 1 m³/min
56.63 m³/min = 0.94 m³/s
Thus, 2×10³ ft³/minis equivalent to 0.94 m³/s.
