If a certain mass of mercury has a volume of 0.002 m^3 at a temperature of 20°c, what will be the volume at 50°c
2 answers:
Change in volume = mass x coefficient of linear expansion x change in temperature
.002 x .0001802 x 30 = .000010812
initial volume + change in volume = Final volume
.002 + .000010812 = .002010812 m cubed
<h3><u>Answer;</u></h3>
<em><u>= 0.0020108 m³</u></em>
<h3><u>
Explanation;</u></h3>
- Using the concept on thermal expansion of matter, in this case thermal expansion of liquid mercury.
V₁=0.002 m³, T₂ =20 °C
V₂= ? T₂ = 50° C
- Thus, change in temperature will be; T₂ - T₁
That is, 50°C - 20°C = 30 °C
- The coefficient (γ) of volume expansion of Mercury at 20 °C is 0.00018 per centigrade.
- Therefore, the volume of mercury at 50° C will be given by;
V₂ =V₁ [1 + γ(50-30)]
= 0.002 [1 + 0.00018(30)]
= 0.0020108 m³
Therefore; the volume of mercury at 50°C is 0.0020108 m³
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hi <3
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