Please help fast!! I need someone to see if my answers are correct! If any are wrong please let me know what the correct answers
1 answer:
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The given elements put into an equation using their symbols are as follows:
Pb +
= 
+ Ag
Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + = + Ag
Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb +
= + Ag
Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + = + 2Ag
That is your final equation
The coefficients are 2 + 2 = 1 + 2
Pb +
Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb +
Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb +
Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb +
That is your final equation
The coefficients are 2 + 2 = 1 + 2
Volume of NaOH required to react = 145.5 ml
<h3>Further explanation</h3>Reaction
CO₂(g) + 2 NaOH(aq) ⇒Na₂CO₃(aq) + H₂O(l)
The volume of CO₂ : 0.45 L
mol CO₂ at STP (O C, 1 atm) ⇒ at STP 1 mol gas 22.4 L :
From the equation, the mol ratio of CO₂ : NaOH = 1 : 2, so mol NaOH :
Then volume of NaOH :
Answer: The molarity of each of the given solutions is:
(a) 1.38 M
(b) 0.94 M
(c) 1.182 M
Explanation:
Molarity is the number of moles of a substance present in liter of a solution.
And, moles is the mass of a substance divided by its molar mass.
(a) Moles of ethanol (molar mass = 46 g/mol) is as follows.
Now, molarity of ethanol solution is as follows.
(b) Moles of sucrose (molar mass = 342.3 g/mol) is as follows.
Now, molarity of sucrose solution is as follows.
(c) Moles of sodium chloride (molar mass = 58.44 g/mol) are as follows.
Now, molarity of sodium chloride solution is as follows.
Thus, we can conclude that the molarity of each of the given solutions is:
(a) 1.38 M
(b) 0.94 M
(c) 1.182 M