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Feliz [49]
2 years ago
12

How many moles of nitrous oxide gas (N2O) is contained in 20.0 L balloon at a pressure of 1.09 atm and a temperature of 298K? Ro

und to the nearest hundredths place.
Chemistry
1 answer:
prohojiy [21]2 years ago
7 0

Answer:

There are 0,89 moles of nitrous oxide gas  in the balloon.

Explanation:

We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:

PV= nRT ---> n= PV/RT

n= 1,09 atm x 20,0 L /0.082 l atm / K mol x 298 K

<em>n= 0,89212637 mol</em>

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A rock that weighs 12.2 g is added to a graduated cylinder with 30.0 mL of water in it. The meniscus rises to 54.4 mL. What is t
GuDViN [60]

Answer:

              0.50 g/mL

Explanation:

Formula of Density,

                          D = mass / volume

Mass = 12.2 g

Volume = 54.4 mL - 30.0 mL = 24.4 mL

Putting values,

                          D = 12.2 g / 24.4 mL

                          D = 0.50 g/mL

4 0
2 years ago
Please Please Please Please Please Help Me (please answer this question completely and 1 will friend you and help you with your
pav-90 [236]

Answer:

Static electricity is a type of energy that is produced by friction.

Explanation:

Static electricity may be the result when there is an imbalance between the negative charges and the positive charges in the surroundings. They are non contact forces. They pull of push without actually touching the body. The charged particles interact by pulling or pushing the uncharged particles.

These charges are released when they come closer to some uncharged or other charged particles like the electrostatic charges. It is the charge build up in an area.

6 0
3 years ago
How many grams of F2 gas are there in a 5.00-L cylinder at 4.00 × 10^3 mm Hg and 23°C?
GuDViN [60]

Answer:

41.17g

Explanation:

We are given the following parameters for Flourine gas(F2).

Volume = 5.00L

Pressure = 4.00× 10³mmHG

Temperature =23°c

The formula we would be applying is Ideal gas law

PV = nRT

Step 1

We find the number of moles of Flourine gas present.

T = 23°C

Converting to Kelvin

= °C + 273k

= 23°C + 273k

= 296k

V = Volume = 5.00L

R = 0.08206L.atm/mol.K

P = Pressure (in atm)

In the question, the pressure is given as 4.00 × 10³mmHg

Converting to atm(atmosphere)

1 mmHg = 0.00131579atm

4.00 × 10³ =

Cross Multiply

4.00 × 10³ × 0.00131579atm

= 5.263159 atm

The formula for number of moles =

n = PV/RT

n = 5.263159 atm × 5.00L/0.08206L.atm/mol.K × 296K

n = 1.0834112811moles

Step 2

We calculate the mass of Flourine gas

The molar mass of Flourine gas =

F2 = 19 × 2

= 38 g/mol

Mass of Flourine gas = Molar mass of Flourine gas × No of moles

Mass = 38g/mol × 1.0834112811moles

41.169628682grams

Approximately = 41.17 grams.

3 0
2 years ago
How many grams of solute are needed to prepare a 3.50% mass/mass solution that has a solution mass of 2.50x102 grams.
Elis [28]
One way of expressing concentration is by percent. It may be on the basis of mass, mole or volume. Percent is expressed as the amount of solute per amount of the solution. For this case, we are given the percent by mass. In order to solve the amount of solute, we multiply the percent with the amount of the solution.

Mass of solute = percent by mass x mass solution
Mass of solute = 0.0350 x 2.50 x10^2 = 8.75 grams of solute
5 0
3 years ago
Calculate number of moles of 4.4g of CO2 and 5.6L of NH3 . Pls help . Its urgent
kupik [55]
Moles of CO₂ = mass / molecular weight
Moles of CO₂ = 4.4 / (12 + 16 x 2)
Moles of CO₂ = 0.1 mol

Each mole of gas occupies 22.4 L at STP. Therefore,
Moles of NH₃ = 5.6 / 22.4
Moles of NH₃ = 0.25 mol
4 0
3 years ago
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