<u>Answer:</u>
Law used: Combined Gas Law
<u>Explanation:</u>
We are given the following problem:
Carbon dioxide is in a steel tank at 20°C, 10 liters and 1 atm. What is the pressure on the gas when the tank is heated to 100°C?
To solve this, the most appropriate law that can be used it Combined Gas Law, which is the result of combining the Boyle's law, Charles' law, and Gay-Lussac's law together.
Although there isn’t a picture a graph can be misleading when it doesn’t start at zero, it doesn’t give accurate information, it skips too many numbers, the vertical scale is too big or too small. Hope this helps
Answer:
- 278.85 J
Explanation:
Given that:
Pressure = 1.1 atm
The initial volume V₁ = 0.0 L
The final volume V₂ = 2.5 L
The work that takes place in a reaction at constant pressure can be expressed by using the equation:
W = P(V₂ - V₁ )
Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:
W = - P(V₂ - V₁ )
W = -1.1 atm ( 2.5 - 0.0) L
W = -1.1 atm (2.5 L)
W = -2.75 atm L
Recall that:
1 atm L = 101.4 J
Therefore;
-2.75 atm L = ( -2.75 × 101.4 )J
= -278.85 J
Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm = - 278.85 J
The liquid that is expected to have the weakest intermolecular interaction is the liquid that has the lowest boiling point and surface tension.
<h3>What is boiling point?</h3>
The term boiling point refers to the temperature at which the atmospheric pressure and the pressure of the liquid becomes equal. The greater the intermolecular forces of attraction between molecules the higher the boiling point of the solid. Also a high surface tension indicates a strong intermolecular forces of attraction between molecules.
The liquid that is expected to have the weakest intermolecular interaction is the liquid that has the lowest boiling point and surface tension.
Learn more about boiling points: brainly.com/question/2153588
I can not answer your question because i am a person who is not smart
and will never become smart
