Answer:
3.94 L
Explanation:
From the question given above, the following data were obtained:
Mass of O₂ = 5.62 g
Volume of O₂ =?
Next, we shall determine the number of mole present in 5.62 g of O₂. This can be obtained as follow:
Mass of O₂ = 5.62 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mole of O₂ =?
Mole = mass / molar mass
Mole of O₂ = 5.62 / 32
Mole of O₂ = 0.176 mole
Finally, we shall determine the volume of 5.62 g (i.e 0.176 mole) of O₂ at STP. This can be obtained as follow:
1 mole of O₂ occupied 22.4 L at STP.
Therefore, 0.176 mole of O₂ will occupy = 0.176 × 22.4 = 3.94 L at STP.
Thus 5.62 g (i.e 0.176 mole) of O₂ occupied 3.94 L at STP
Sodium Hydroxide is known as Lye.
Answer:
4FeS + 7O₂ ----> 2Fe₂O₃ + 4SO₂
Explanation:
You have to drag the elements shown on the right under the formula. For example, you would have to drag 4 of the FeS molecules under the 4FeS text in the formula. Then place 7 O₂ molecules under the 7O₂ text, etc.
1) during daylight, especially around noon, the relatively high air **temperature** and low humidity caused high evaporation, extracting pore water from the beach and leaving the **salt** behind, thereby resulting in high salinity near the beach surface (intertidal zone)
2) • algae and other intertidal plants grow in the abundant sunlight and support an entire food chain of animals
• constant wave action supplies the tide pool with **nutrients** and oxygen
• food is abundant
• a varied substrate provides hiding places and surfaces to cling to
3) the intertidal zone is one of a number of **marine** biomes or habitats, including: estuary (spray zone), neritic (lower/shallow zone), surface (middle zone), deep zones (high zones)
