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Nata [24]
4 years ago
10

Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN3) into so

lid sodium and gaseous dinitrogen. Suppose 22.0 L of dinitrogen gas are produced by this reaction, at a temperature of 11.0 C and pressure of exactly 1 atm. Calculate the mass of sodium azide that must have reacted.

Chemistry
1 answer:
LenaWriter [7]4 years ago
5 0

Answer:

39g

Explanation:

Details of the solution is shown below. From the information provided regarding the N2 produced, we could calculate the amount of N2 produced and use that to find the mass of sodium azide reacted.

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What is Acid and any type of acid​
finlep [7]

Answer:

Acid is the substance which gives H+ ions when dissolved in an aqueous solution and tastes sour.

Types of acid

  1. Strong acid
  2. Weak acid
6 0
3 years ago
Read 2 more answers
Calculate the amount of heat energy, in units of kilojoules, required to convert 50.0 g of liquid ethanol, CH3CH2OH, at 25.5°C t
tamaranim1 [39]

Answer:

42.1 kj

Explanation:

Given data:

Molar heat of vaporization = 3.86×10⁴ j/mol

Mass of ethanol = 50 g

Amount of heat required to convert into gaseous form = ?

Solution:

First of all we will calculate the number of moles of ethanol.

Number of moles = mass/ molar mass

Number of moles = 50.0 g/ 46.07 g/mol

Number of moles = 1.09 mol

H(vap) = number of moles × molar heat of vaporization

H(vap) =  1.09 mol × 3.86×10⁴ j/mol

H(vap) = 4.21×10⁴ j

In Kj:

4.21×10⁴ / 1000 = 42.1 kj

7 0
4 years ago
Three lab groups carried out an experiment to identify the correct molarities for five solutions. Each unknown contained one of
guajiro [1.7K]

Answer:

B) Osmosis of water molecules from unknown solution A likely caused the increase in mass observed.

Explanation:

Osmosis is a type of <em>diffusion </em>(a random movement of molecules to an area of lower concentration from an area of higher concentration) of water. Like other molecules, water can pass through a cell membrane and it will diffuse across the membrane, along its own concentration gradient independent of other particles that could be present in solution. The concentration of water in a solution is <em>inversely </em>(opposite) related to the concentration of the solute, meaning that water will move from a region of high water potential to a region of lower water potential during osmosis.

Unknown solution A had the highest water potential with a sucrose concentration of 0.0 M. This means that water diffused through the membranes of the cells in the sweet potato cube as it moved along its own <em>concentration gradient</em> (from a region of high water potential to a region of lower water potential) causing an increase in the mass of the sweet potato cube

3 0
4 years ago
How many grams of C6H6O3 will react with 97.0grams of O2?<br><br> C6H6O3+3O2 ===&gt; 6CO+3H2O
likoan [24]

Answer:

127.3 g

Explanation:

Data Given

mass of O₂= 97 g

mass of C₆H₆O₃ = ?

Reaction Given:

                C₆H₆O₃ + 3O₂ -------->  6CO + 3H₂O

Solution:

First find the mass of C₆H₆O₃ from the reaction that it combine with how many grams of oxygen (O₂).

Look at the balanced reaction

                  C₆H₆O₃  +   3O₂       -------->  6CO + 3H₂O

                    1 mol        3 mol

So 1 mole of C₆H₆O₃ combine with 3 moles of O₂  

Now

convert the moles into mass for which we have to know molar mass of C₆H₆O₃ and O₂

Molar mass of C₆H₆O₃

Molar mass of C₆H₆O₃ = 6(12) + 6(1) +3(16) = 72 + 6 + 48

Molar mass of C₆H₆O₃ = 126 g/mol

mass of C₆H₆O₃

                 mass in grams = no. of moles x molar mass

                 mass of C₆H₆O₃ = 1 mol x 126 g/mol

                 mass of C₆H₆O₃ = 126 g

Molar mass of O₂ = 2(16)

Molar mass of O₂= 32 g/mol

mass of O₂

                mass in grams = no. of moles x molar mass

                mass of O₂ = 3 mol x 32 g/mol

                 mass of O₂ = 96 g

So,

96 g of O₂ combine with 126 g of C₆H₆O₃ then how many grams of C₆H₆O₃ will combine with 97.0grams of O2

Apply unity Formula

                      96 g of O₂ ≅ 126 g of C₆H₆O₃

                      97 g of O₂ ≅  X g of C₆H₆O₃

By cross multiplication

                    X g of O₂ = 126 g x 97 g / 96 g

                   X g  of O₂ = 127.3 g

127.3 g of C₆H₆O₃ will combine with 97 g of O₂

So

mass of C₆H₆O =  127.3 g

7 0
3 years ago
Calculate the formula mass of calcium iodate, ca(io3)2, in atomic mass units (amu or u).
VARVARA [1.3K]
<span>389.88094 amu First we look up the atomic mass of all elements contained in calcium iodate using the periodic table: Ca: 40.078 I: 126.90447 O: 15.999 As an intermediate step we calculate the molecular mass of the ion IO3: 126.90447 + 3*15.999 = 174.90147 Then we calculate the mass of one calcium atom and 2 iodate ions: 2*174.90147 + 40.078 = 389.88094 amu</span>
7 0
3 years ago
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