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mojhsa [17]
3 years ago
12

Which statements correctly describe the rock cycle? Check all that apply.

Chemistry
1 answer:
pickupchik [31]3 years ago
3 0

Answer: I italicize for checking

  1. <em>Rocks are preserved through the process.</em>
  2. <em>Rocks change from one type to another.</em>
  3. <em>Different rock groups are interrelated.</em>
  4. Rocks change from one type to another in a specific order.
  5. <em>Environmental conditions influence a change in rock type.</em>

Explanation:

Rocks are preserved, as in you can't destroy them completely, but no, they don't <em>stay </em>the same they change.

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6. The graph below shows the heating curve for ethanol (from –200C to 150C). Calculate the amount of heat (kJ) required for each
Kazeer [188]

This problem is providing the heating curve of ethanol showing relevant data such as the initial and final temperature, melting and boiling points, enthalpies of fusion and vaporization and specific heat of solid, liquid and gaseous ethanol, so that the overall heat is required and found to be 1.758 kJ according to:

<h3>Heating curves:</h3>

In chemistry, we widely use heating curves in order to figure out the required heat to take a substance from a temperature to another. This process may involve sensible heat and latent heat, when increasing or decreasing the temperature and changing the phase, respectively.

Thus, since ethanol starts off solid and end up being a vapor, we will find five types of heat, three of them related to the heating-up of ethanol, firstly solid, next liquid and then vapor, and the other two to its fusion and vaporization as shown below:

Q_T=Q_1+Q_2+Q_3+Q_4+Q_5

Hence, we begin by calculating each heat as follows, considering 1 g of ethanol is equivalent to 0.0217 mol:

Q_1=0.0217mol*111.5\frac{J}{mol*\°C}[(-114.1\°C)-(-200\°C)] *\frac{1kJ}{1000J} =0.208kJ\\&#10;\\&#10;Q_2=0.0217mol*4.9\frac{kJ}{mol} =0.106kJ\\&#10;\\&#10;Q_3=0.0217mol*112.4\frac{J}{mol*\°C}[(78.4\°C)-(-114.1\°C)] *\frac{1kJ}{1000J} =0.470kJ\\&#10;\\&#10;Q_4=0.0217mol*38.6\frac{kJ}{mol} =0.838kJ\\&#10;\\&#10;Q_5=0.0217mol*87.5\frac{J}{mol*\°C}[(150\°C)-(78.4\°C)] *\frac{1kJ}{1000J} =0.136kJ

Finally, we add them up to get the result:

Q_T=0.208kJ+0.106kJ+0.470kJ+0.838kJ+0.136kJ\\&#10;\\&#10;Q_T=1.758kJ

Learn more about heating curves: brainly.com/question/10481356

7 0
2 years ago
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