Two non-polar molecules are most likely to interact by
induced dipole-induced dipole interaction.
Non-polar substances do not have a permanently established charge distribution due to similar electron affinities of the atoms that are present. Moreover, due to the absence of a polar hydrogen, they cannot exhibit hydrogen bonding. They interact with one another by induced dipole-induced dipole interactions which arise from the molecules of the substances coming into close vicinity of one another.
Answer:
A white dwarf is what stars like the Sun become after they have exhausted their nuclear fuel. Near the end of its nuclear burning stage, this type of star expels most of its outer material, creating a planetary nebula. Only the hot core of the star remains. ... That means a white dwarf is 200,000 times as dense.
Explanation:
they are cold
they are about the size of Earth
these both are not true
0.003 moles of NaOH was used in the titration.
<h3>What is titration?</h3>
The concentration of an identified analyte can be found using a simple laboratory technique called titration. As a standard solution with a given concentration and volume, a reagent known as the titrant or titrator is created.
By using a solution with a known concentration to measure the concentration of an unknown solution, this process is known as titration. To a known volume of the analyte (the unknown solution), the titrant (the known solution) is typically added from a buret until the reaction is finished. To ascertain the unknown concentration of an identifiable analyte, titration, commonly referred to as titrimetry, is a widely used quantitative laboratory analytical technique (Medwick and Kirschner, 2010). Volume measurements are a crucial component of titration
Concentration in mol/dm3 =
Amount of solution mol
= concentration in mol/dm3 × volume in dm3
Amount of sodium hydroxide
= 0.100 × 0.0250
= 0.00250 mol
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Remember this:
1) n is principal quantum number and represents the energy level.
2) l is the second quantum number and represent the type of orbital.
3) l can take values from 0 to n - 1
4) each number of l is associated with a type of orbital. This table shows the equivalence:
l number type of orbital
0 s
1 p
2 d
3 f
With that, you can tell that n = 2 permits l = 0 and 1, which is orbitals s and p.
Therefore, the answer is the option D) s, p.
Endothermic or C, if you would like a reason why, do not hestitate to ask
