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ANEK [815]
3 years ago
10

You want to build a greenhouse from at most 500 square feet of material in the shape of a half cylinder. The surface area of the

greenhouse is given by the formula
S = \pi rh + \pi r^2

Where r is the radius and h is the length of the greenhouse.
Write an expression for h in the terms of r.
Then find all of the possible values of r
Mathematics
1 answer:
dybincka [34]3 years ago
4 0
<span>Expression for h is h = 500/(pi * r) - r Range of values for r = (0, 10sqrt(5/pi)] First, let's substitute the maximum area of the greenhouse into the provided equation. 500 = pi * r * h + pi * r^2 Now solve for h 500 = pi * r * h + pi * r^2 500 - pi * r^2 = pi * r * h (500 - pi * r^2) / pi * r = h 500/(pi * r) - r = h The minimum value for r is just above 0, since at 0, you're attempting to divide by 0. The maximum value for r is where h = 0, so let's substitute 0 for h and solve for r, giving 500/(pi * r) - r = h 500/(pi * r) - r = 0 500/(pi * r) = r 500 = pi * r^2 500/pi = r^2 sqrt(500/pi) = r 10sqrt(5/pi) = r So maximum r is approximately 12.616 ft. The range of values for r is (0, 10sqrt(5/pi)] e.g. You're not allowed to quite reach the lower limit since that would attempt to divide by 0, but you're allowed to go all the way to the upper limit.</span>
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4 0
3 years ago
Raymond can type 40 words each minute. How many words can he type in 8 minutes?
Phantasy [73]

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320

Step-by-step explanation:

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3 0
3 years ago
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7 0
3 years ago
Rain began failling at 2:18 . It rained for 1 hour and 36 minutes
prisoha [69]

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4 0
3 years ago
Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.
SOVA2 [1]

Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at (0,1).

The graph has an x-intercept at (-7,0).

Step-by-step explanation:

Given: The graph is y=\sqrt[3]{x-1}+2

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of (-\infty, \infty).

To find the y-intercept:  To find the y-intercept, substitute x=0 in y=\sqrt[3]{x-1}+2.

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}

Thus, the y-intercept is (0,1)

To find the x-intercept: To find the x-intercept, substitute y=0 in y=\sqrt[3]{x-1}+2 .

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}

Thus, the x-intercept is (-7,0)

8 0
3 years ago
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