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TiliK225 [7]
3 years ago
10

What molecules are found in all or almost all organic compounds?

Chemistry
2 answers:
klemol [59]3 years ago
5 0
D. <span>carbon and hydrogen</span>
Gnoma [55]3 years ago
4 0

<u>Answer:</u> The correct answer is Option d.

<u>Explanation:</u>

Organic compounds are defined as the compounds which are found in living organisms.

These compounds mainly consists of carbon atoms which are covalently bonded to hydrogen, oxygen and nitrogen atoms.

<u>For Example:</u>  C_{5}H_{11}O,HCN

Both the compounds are organic compounds because carbon is bonded to nitrogen, oxygen and hydrogen atoms.

Main elements present in any organic compound are carbon and hydrogen.

Hence, the correct answer is Option d.

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Explain why the weight of an object changes if taken to the moon but not its mass​
avanturin [10]

Answer:

Because the gravitational force alters

Explanation:

3 0
3 years ago
You have decided to test the effects of five garden fertilizers by applying some of each to five separate rows of radishes. what
attashe74 [19]

You are testing which fertilizer makes the radishes grow the fastest.

factors you should control: sunlight exposure, water amount, fertilizer amount.

Measure: check the rows of radishes to see how much each row has grown in comparison to the others. Whichever row with the healthiest radishes has the best fertilizer.

5 0
3 years ago
What is the correct formula for Heptarsenic Tetrabromide
harina [27]
Hepta is seven and tetra is four, so option c is your answer
3 0
3 years ago
What is the maximum number of moles of N-acetyl-p-toluidine can be prepared from 70. milliliters of 0.167 M p-toluidine hydrochl
Kitty [74]

Answer:

\large \boxed{\text{0.012 mol}}  

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

               CH₃C₆H₄NH₂·HCl + (CH₃CO)₂O ⟶ CH₃C₆H₄NHCOCH₃ + junk

V/mL:                    70.

c/mol·L⁻¹:             0.167

For simplicity in writing , let's call p-toluidine hydrochloride A and N-acetyl-<em>p</em>-toluidine B.

The equation is then

A + Ac₂O ⟶ B + junk

1. Moles of A

\text{Moles of A} = \text{70. mL A}\times \dfrac{\text{0.167 mmol A}}{\text{1 mL A}}= \text{12 mmol A}

2. Moles of B

The molar ratio is 1 mol B:1 mol A

Moles of B = moles of A = 12 mmol = 0.012 mol

\text{You can prepare $\large \boxed{\textbf{0.012 mol}}$ of N-acetyl-p-toluidine. }

3 0
3 years ago
13. A mixture of MgCO3 and MgCO3.3H2O has a mass of 3.883 g. After heating to drive off all the water the mass is 2.927 g. What
rjkz [21]

Answer:

63.05% of MgCO3.3H2O by mass

Explanation:

<em>of MgCO3.3H2O in the mixture?</em>

The difference in masses after heating the mixture = Mass of water. With the mass of water we can find its moles and the moles and mass of MgCO3.3H2O to find the mass percent as follows:

<em>Mass water:</em>

3.883g - 2.927g = 0.956g water

<em>Moles water -18.01g/mol-</em>

0.956g water * (1mol/18.01g) = 0.05308 moles H2O.

<em>Moles MgCO3.3H2O:</em>

0.05308 moles H2O * (1mol MgCO3.3H2O / 3mol H2O) =

0.01769 moles MgCO3.3H2O

<em>Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-</em>

0.01769 moles MgCO3.3H2O * (138.3597g/mol) = 2.448g MgCO3.3H2O

<em>Mass percent:</em>

2.448g MgCO3.3H2O / 3.883g Mixture * 100 =

<h3>63.05% of MgCO3.3H2O by mass</h3>
6 0
3 years ago
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