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3 years ago

Prevent a page break in the final paragraph of this document by keeping the lines together

Computers and Technology

1 answer:

sineoko [7]3 years ago

7 0

Answer:

1. Place your cursor in the General Provisions section towards the finish of the archive.

2. On the Page Layout tab, in the Paragraph gathering, tap the Paragraph Dialog Box Launcher and afterward tap the Line and Paragraph Breaks tab.

3. Select the Keep lines together checkbox and snap Ok.

Explanation:

In a short report or one that doesn't require a complex navigational structure, you can without much of a stretch configuration words and sections so key focuses emerge and the structure of your record is clear. You can accomplish sensational by applying predefined Word Art content impacts. To keep the presence of reports and other Microsoft Office records steady, you can organize archive components by applying predefined sets of designing called styles. Moreover, you can change the textual styles, hues, and impacts all through a record with a single tick by applying a subject.

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Given the int variables x, y, and z, write a fragment of code that assigns the smallest of x, y, and z to another int variable m

Marysya12 [62]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables

int x=5,y=2,z=9;

int min;

// find the smallest value and assign to min

// if x is smallest

if(x < y && x < z)

// assign x to min

min=x;

// if y is smallest

else if(y < z)

// assign y to min

min=y;

// if z is smallest

else

// assign z to min

min=z;

// print the smallest

cout<<"smallest value is:"<<min<<endl;

return 0;

}

Explanation:

Declare and initialize variables x=5,y=2 and z=9.Then check if x is less than y and x is less than z, assign value of x to variable "min" .Else if value of y is less than value of z then smallest value is y, assign value of y to "min".Else z will be the smallest value, assign its value to "min".

Output:

smallest value is:2

6 0

2 years ago

Write a program that reads a list of integers into a list as long as the integers are greater than zero, then outputs the smalle

almond37 [142]

Answer:

Check the explanation

Explanation:

-6

the output will be somthing like this:

2 21

You can then suppose that the list of integers will contain at least 2 values.

4 0

3 years ago

Can you prove that the bleu areas are the same please?

Nookie1986 [14]

$\huge\color{darkred}{ \tt{NO!!}}$

8 0

2 years ago

Read 2 more answers

Define a void function that calculates the sum (+), difference (-), product (*), quotient (/), and modulus (%) of two integer nu

BabaBlast [244]

Answer:

#include <iostream>

using namespace std;

void multipurpose(int &num1,int &num2,int &add,int &subt,int &multi,int &divi,int &modulo )

{

add=num1+num2;//adding two numbers...

subt=abs(num1-num2);//subtracting two numbers...

multi=num1*num2;//multiplying two numbers...

divi=num1/num2;//Finding quotient of two numbers...

modulo=num1%num2;//Finding modulo of two numbers...

}

void print(int add,int sub,int divi,int multi,int modulo) //function to print the values.

{

cout<<"The addition is "<<add<<endl<<"The subtraction is "<<sub<<endl

<<"The quotient is "<<divi<<endl<<"The multiplication is "<<multi<<endl

<<"The modulus is "<<modulo<<endl;

}

int main() {

int a,b,sum=0,mult=0,divi=0,sub=0,modulo=0;

cin>>a>>b;

multipurpose(a,b,sum,sub,mult,divi,modulo);

print(sum,sub,divi,mult,modulo);

return 0;

}

Enter the numbers

12 12

The addition is 24

The subtraction is 0

The quotient is 1

The multiplication is 144

The modulus is 0

Explanation:

I have created a function multipurpose that has a argument list of two numbers ,and variables for addition,subtraction,multiplication,Division,Modulus and these all are passed by reference.Since the function is of type void so it cannot return anything so the only way to store the result is by passing the variables to store the results by reference.

The other function print has the arguments of all the results here you can pass them by value or by reference because you only need to print the results.

7 0

3 years ago

1. Create an interface called Runner. The interface has an abstract method called run() that display a message describing the me

Colt1911 [192]

Answer:

see explaination for program code

Explanation:

interface Runner

{

public abstract void run();

}

class Machine implements Runner

{

public void run()

{

System.out.println("Machine is running");

}

class Athlete implements Runner

{

public void run()

{

System.out.println("Athlete is running");

}

class PoliticalCandidate implements Runner

{

public void run()

{

System.out.println("Political Candidate is running");

}

class DemoRunners

{

public static void main (String[] args)

{

Machine m = new Machine();

m.run();

Athlete a = new Athlete();

a.run();

PoliticalCandidate pc = new PoliticalCandidate();

pc.run();

}

7 0

3 years ago