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Fed [463]
3 years ago
11

Chemical equation use symbols instead of words it is that true or false

Chemistry
1 answer:
fgiga [73]3 years ago
8 0
The answer is true. I believe
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5g of aspirin will powder will take effect more quickly than a 5g aspirin tablet because the powder has more what
Pani-rosa [81]

Answer:

Explanation:

Because the powder has more finer and larger surface area hence it absorbed faster and it becomes more effective in performance compared to the tablet that will still need to be dissolved before it is been assimilated into the body system.

7 0
4 years ago
How did mendeleev orginally organize the element in his periodic table
horrorfan [7]
From increasing atomic mass. He also made groups and periods.
4 0
4 years ago
Read 2 more answers
Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2N
Vitek1552 [10]

Answer : The value of work done for the system is 1144.69 J

Explanation :

First we have to calculate the moles of NaN_3

\text{Moles of }NaN_3=\frac{\text{Mass of }NaN_3}{\text{Molar mass of }NaN_3}

Molar mass of NaN_3 = 65.01 g/mole

\text{Moles of }NaN_3=\frac{20.2g}{65.01g/mole}=0.311mole

Now we have to calculate the moles of nitrogen gas.

The balanced chemical reaction is,

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 2 mole of NaN_3 react to give 3 mole of N_2

So, 0.311 moles of NaN_3 react to give \frac{0.311}{2}\times 3=0.466 moles of N_2

Now we have to calculate the volume of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = ?

n = number of moles N_2 = 0.466 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 22^oC=273+22=295K

Putting values in above equation, we get:

1.00atm\times V=0.466mole\times (0.0821L.atm/mol.K)\times 295K

V=11.3L

As initially no nitrogen was present. So,

Volume expanded = Volume of nitrogen evolved

Thus,

Expansion work = Pressure × Volume

Expansion work = 1.00 atm × 11.3 L

Expansion work = 11.3 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 11.3 × 101.3 = 1144.69 J

Therefore, the value of work done for the system is 1144.69 J

5 0
3 years ago
What is the angle between the carbon-sulfur bond and the carbon-nitrogen bond in the thiocyanate ( SCN− ) ion?
KIM [24]
I’m not completely sure
4 0
4 years ago
Read 2 more answers
A stover-to-ethanol plant produces 40,000 tonne/yr of ethanol and contains 8functionalunits:feedstockhandling,pretreatment,simul
Step2247 [10]

Answer:

FCI=458000*8*40000^{0.3}\\FCI=880818398.52 M

FCI=88.0818 MM≅88 MM

Explanation:

Empirical correlation based on the work of Bridgwater and Mumford (1979):

For Liquid or solid phase Plants:

FCI=458000*N*F^{0.3}                       F<60,000 tonne/yr     Eq (1)

FCI=7000*N*F^{0.68}                         F≥60,000 tonnes/yr   Eq (2)

Where:

N is the number of functional units

F is the process throughput tonnes/yr

In our case F=40,000 tonne/yr <60,000 tonne/yr, We are going to use Eq (1)

FCI=458000*N*F^{0.3}                       F<60,000 tonne/yr

N=8, F=40,000 tonne/yr

FCI=458000*8*40000^{0.3}\\FCI=880818398.52 M

FCI=88.0818 MM≅88 MM

8 0
3 years ago
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