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user100 [1]
2 years ago
14

Consider the reaction:

Chemistry
1 answer:
Vesna [10]2 years ago
7 0

Answer:

The correct answer is E.

Explanation:

Given the reaction:

C₂H₅OH (l) + 3 O₂(g) ⇒ 2 CO₂ (g) + 3 H₂O (l) ; ΔH = -1.37×10³ kJ

We can see that ΔH is negative. This means that the product formation energy is less than the reagent formation energy. In other words, the reaction releases heat and is therefore an exothermic reaction.

In addition, the enthalpy of formation of liquid water has different value than the enthalpy of formation of gaseous water. Therefore, the enthalpy variation would have a different value if the water formed was in a gaseous state.

Finally, the propositions II and III are true.

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Help please!!!!!! ASAP
uysha [10]

Answer:

Have you tried googling it

5 0
3 years ago
An object is hit with a force of 5 Newtons and accelerates to 36 m/s2. What is the mass of the object
mrs_skeptik [129]

Answer:

Mass = 0.139 kg

Explanation:

There is a formula in terms of force, acceleration and mass which is:

Force = mass × acceleration

Put the values into the formula.

5 = m × 36

m = 5 ÷ 36

<u>m = 0.139 kg</u>

6 0
2 years ago
What is the balanced chemical equation for cellular respiration?
ANEK [815]
Glucose + Oxygen > Carbon Dioxide
C(6)H(12)0(6)+ 0(2) >CO(2)
8 0
3 years ago
An example of a suspension is:<br> A. blood<br> B. gelatin<br> C. muddy water<br> D. milk
Shkiper50 [21]
ANSWER:A.blood

WHY: because it make the most sense and it seem right


Can I get brainly
3 0
3 years ago
How many grams of argon would it take to fill a large light bulb with a volume of 0.745 L at STP?
EastWind [94]

Answer:

Mass = 1.33 g

Explanation:

Given data:

Mass of argon required = ?

Volume of bulb = 0.745 L

Temperature and pressure = standard

Solution:

We will calculate the number of moles of argon first.

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

By putting values,

1 atm ×0.745 L = n × 0.0821 atm.L/mol.K× 273.15 K

0.745 atm. L = n × 22.43 atm.L/mol

n = 0.745 atm. L / 22.43 atm.L/mol

n = 0.0332 mol

Mass of argon:

Mass = number of moles × molar mass

Mass = 0.0332 mol × 39.95 g/mol

Mass = 1.33 g

8 0
2 years ago
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