Answer:
Domain : {x | all real numbers} ; Range: {y | y > 0}
Step-by-step explanation:
The function can be written as :
![f(x)=\sqrt[\frac{2}{3}]{108^{2\cdot x}}\\\\\implies f(x)=(108)^{(\frac{3}{2})^{2\cdot x}}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B%5Cfrac%7B2%7D%7B3%7D%5D%7B108%5E%7B2%5Ccdot%20x%7D%7D%5C%5C%5C%5C%5Cimplies%20f%28x%29%3D%28108%29%5E%7B%28%5Cfrac%7B3%7D%7B2%7D%29%5E%7B2%5Ccdot%20x%7D%7D)
Now, since x is exponent so it can take any real values. So, its domain of f(x) is all real numbers
But value of f(x) can not be less than 1 because for x = 0 the value of f(x) is 1 and also for any values of x, the value of f(x) can never be less than 1
So, Range of f(x) is all real numbers greater than 0
Hence, Domain and Range of f(x) is given by :
Domain : {x | all real numbers} ;
Range: {y | y > 0}
So this is a two step process, first you must find the area of the rectangle, then find the area of the semicircle.
So to find the area of a rectangle, you use: Length*Height=Area
In this case that would be: 7*2=14cm
Next you find the area of the semicircle, to do this you first find the area of the circle (Pi*r^2) then divide it by 2.
The diameter of the circle is 4 because: 7-2-1=4cm
Next divide that by 2 so that you get the radius: 4/2=2cm
Not you can plug that into the equation to get the area of the circle: Pi*2^2<span>≈13cm^2
Next divide it by 2 so that you get the area of the semicircle:13/2</span><span><span>≈</span>6cm^2
At this point you can add the area of the semicircle to the area of the rectangle: 14+6=20cm^2
So your final answer is 20cm^2!
</span>
Length of the larger canvas = 6 ft
The scale factor is 2.
5 x 2 = 10 which gave us the width of the larger canvas
So also do 3 x 2 = 6 which is the length of the larger canvas
Answer:
3 1/3π
Step-by-step explanation:
First, you have to find the circumference. The circumference, based on the equation of 2rπ, comes out as 20π. Since you have to find the length of the arc that is 60 degrees, divide 60 by 360 to see how much of the circle 60 degrees is. It results in 1/6, so then you simply have to multiply 20π by 1/6.
