<span><span><span><span>(<span>15^2</span>)</span><span>(<span>y^2</span>)</span></span>−<span>x^3</span></span>+7</span><span>=<span><span><span><span>225<span>y^2</span></span>+</span>−<span>x^3</span></span>+7</span></span>
<span>=<span><span><span>−<span>x^3</span></span>+<span>225<span>y^2</span></span></span>+<span>7</span></span></span>
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Answer:
0.833
Step-by-step explanation:
1. locate which vertical column of the graph we are referring to:
2. calculate the total number of trials student 7 did:
- if in 5 trials the tack landed point-up, and in 1 trial the tack did not land point-up, the total number of trials is 6
- 5 + 1 = 6
3. refer back to the question:
- the question states: "what is the experimental probability that the tack lands point-up"
4. interpret the graph:
- of the 6 trials student 7 underwent, the graph tells us that 5 landed point-up.
- therefore the experimental probability of a tack landing point up is 5/6 (in 5 out of the 6 trials, the tack landed point-up)
5. converting from fraction to decimal:
- all the given answers are given in decimal form, whilst our current answer (5/6) is in fraction form.
- to convert to decimal form, simply divide the top number by the bottom number
- 5 ÷ 6 = 0.833
therefore, the experimental probability that the tack will land point-up, is 0.833
hope this helps :)
Answer:
neither positive nor negative
Step-by-step explanation:
