Question

A line has a slope of 9 and includes the points (t, 7) and (-10, -2). What is the value of t?

Answer 1

T=-9 and the work is there

If you have any questions about what I did

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Answer 2

$\bf (\stackrel{x_1}{t}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{-10}~,~\stackrel{y_2}{-2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-2-7}{-10-t}=\stackrel{\stackrel{slope}{\downarrow }}{9}\implies \cfrac{-9}{-10-t}=9 \\\\\\ -9=-90-9t\implies 81=-9t\implies \cfrac{81}{-9}=t\implies -9=t$