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padilas [110]
3 years ago
10

What temperature does nuclear fusion begin?

Physics
2 answers:
pishuonlain [190]3 years ago
5 0

Answer:

15,000,000 degrees Celsius

Explanation:

After the temperature reaches this degree, nuclear fusion begins to start.

Katena32 [7]3 years ago
3 0
15,000,000 degrees Celsius
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Un objeto de 1400 g de masa se mueve bajo la acción de una fuerza constante con una aceleración de 0,5 m/s2 , sobre una superfic
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Answer:

if you spoke this in english i can help you out

Explanation:

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Consider the circuit shown below V=18.00V. The terminal voltage of the battery is.
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Resistance is current x potential difference. So therefor run wafff
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3 years ago
child slides down a snow‑covered slope on a sled. At the top of the slope, her mother gives her a push to start her off with a s
Strike441 [17]

Answer:

θ = 13.7º

Explanation:

  • According to the work-energy theorem, the change in the kinetic energy of the combined mass of the child and the sled, is equal to the total work done on the object by external forces.
  • The external forces capable to do work on the combination of child +sled, are the friction force (opposing to the displacement), and the component of the weight parallel to the slide.
  • As this last work is just equal to the change in the gravitational potential energy (with opposite sign) , we can write the following equation:

       \Delta K + \Delta U = W_{nc} (1)

  • ΔK, is the change in kinetic energy, as follows:

       \Delta K = \frac{1}{2}* m* (v_{f} ^{2}  - v_{0} ^{2}) (2)

  • ΔU, is the change in the gravitational potential energy.
  • If we choose as our zero reference level, the bottom of the slope, the change in gravitational potential energy will be as follows:

        \Delta U = 0 - m*g*h = -m*g*d* sin\theta (3)

  • Finally, the work done for non-conservative forces, is the work done by the friction force, along the slope, as follows:

        W_{nc} = F_{f} * d * cos 180\º \\\\  = 0.2*m*g*d* cos 180\º = -0.2*m*g*d (4)

  • Replacing (2), (3), and (4) in (1), simplifying common terms, and rearranging, we have:

      \frac{1}{2}* (v_{f} ^{2}  - v_{0} ^{2}) = g*d* sin\theta -0.2*g*d

  • Replacing by the givens and the knowns, we can solve for sin θ, as follows:              \frac{1}{2}*( (4.30 m/s) ^{2}  - (0.75 m/s)^{2}) = 9.8 m/s2*25.5m* sin\theta -0.2*9.8m/s2*25.5m\\ \\ 8.56 (m/s)2 = 250(m/s)2* sin \theta -50 (m/s)2\\ \\ sin \theta = \frac{58.6 (m/s)2}{250 (m/s)2}  = 0.236⇒ θ = sin⁻¹ (0.236) = 13.7º
8 0
3 years ago
Before colliding the momentum of block A is +15.0 kg*m/s, and block B is -35.0 kg*m/s. after, block A has a momentum -12.0 kg*m/
UkoKoshka [18]

The momentum of block B afterwards is -8.0 kg m/s.

Explanation:

We can solve this problem by applying the principle of conservation of momentum.

In fact, the total momentum before and after the collision must be conserved. Therefore, we can write:

p_A + p_B = p_A' + p_B'

where:

p_A = +15.0 kg m/s is the initial momentum of block A

p_B = -35.0 kg m/s is the initial momentum of block B

p_A' = -12.0 kg m/s is the final momentum of block A

p_B' is the final momentum of block B

Solving for p_B', we find:

p_B' = p_A + p_B - p_A' = +15.0 +(-35.0) - (-12.0)=-8.0 kg m/s

So, the momentum of block B afterwards is -8.0 kg m/s.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

3 0
3 years ago
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