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lisov135 [29]
3 years ago
8

Find the energy released when there is a decrease of 0.3kg of material in a nuclear reaction

Physics
1 answer:
MrRissso [65]3 years ago
4 0

Answer:

E = 2.7 x 10¹⁶ J

Explanation:

The release of energy associated with the mass can be calculated by Einstein's mass-energy relation, as follows:

E = mc^2

where,

E = Energy Released = ?

m = mass of material reduced = 0.3 kg

c = speed of light = 3 x 10⁸ m/s

Therefore,

E = (0.3\ kg)(3\ x\ 10^8\ m/s)^2

<u>E = 2.7 x 10¹⁶ J</u>

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Whenever an increasing temperature leads to a quicker movement of elementary particles and a collision, Thermal energy occurs. The hypothesis as per the given statement is provided below.

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In a ballistics test, a 24 g bullet traveling horizontally at 1300 m/s goes through a 25-cm-thick 360 kg stationary target and e
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Answer:

A)0.00022s b)40363.6N c) 0.025m/s

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0.024*1300 + 360*0 = 0.024*930 + 360*V2

31.2 = 22.32+360*V2

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