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Andrews [41]
3 years ago
13

Complete this paragraph regarding dangers from the Sun.

Physics
2 answers:
Firlakuza [10]3 years ago
8 0

Answer:

[1]. b

[2].c

[3].a

[4].b

Explanation:

plato

i just took the test

Ganezh [65]3 years ago
4 0

Answer:

1: B. High-frequency

2:C. Satelites

3:A. Spacecraft

4:B. geomagnetic storms

i just took the test on PLATO

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A golf ball strikes a hard, smooth floor at an angle of 39.8 ° and, as the drawing shows, rebounds at the same angle. The mass o
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Answer:

The magnitude of the impulse is 1.33 kg m/s

Explanation:

please look at the solution in the attached Word file

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3 years ago
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Bobby places a 4.75 cm tall light bulb a distance of 33.2 cm from a concave mirror. If the mirror has a focal length of 28.2, th
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The image distance can be determined using the mirror equation: 1/f = 1/d_o + 1/d_i, where, f is the focal length, d_o is the object distance, and d_i is the image distance. Given that f = 28.2 and d_o = 33.2 cm, the value of d_i is calculated to be 187.248 cm. On the other hand, the image height is obtained using the magnification equation wherein, h_i/h_o = -d_i/d_o, where h_i is the image height and h_o is the object height. Using the given values, h_i is equal to -26.79 cm. Note that the negative sign indicates that the image is inverted. 
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A car speeds up from 12.0 m/s to 16.0 m/s in 8.00s what is the acceleration
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Answer:

0.5m/s²

Explanation:

acceleration =v-u/t

=(16-12)/8

=4/8

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7 0
2 years ago
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Pretend you (80 kg) are making repairs on the outside of the International Space Station. You are floating 20 meters away from t
djyliett [7]

Answer:

32 seconds

Explanation:

m1 = 80 kg

m2 = 10 kg

v2 = 5m/s

According to the property of conservation of momentum, assuming that both you and the bag are stationary before the safety rope comes lose:

m_{1} v_{1} =m_{2} v_{2} \\80v_{1} =10*5 \\v_{1} = 0.625\ m/s

Since the space station is 20 meters away, the time taken to reach it is given by:

t = \frac{20}{0.625}\\t=32\ s

It takes you 32 seconds to reach the station.

7 0
2 years ago
Shareen finds that when she drives her motorboat upstream she can travelwith a speed of only 8 m/s, while she moves with a speed
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Let vb be the velocity of the motorboat and let vs be the velocity of the stream.

We know that when she drives upstream the velocity is 8 m/s, in this scenario the velocities point in opposite directions, then we have the equations:

v_b-v_s=8

When she drives downstream the velocites point in the same direction then we have the equation:

v_b+v_s=12

hence we have the system of equations:

\begin{gathered} v_b-v_s=8 \\ v_b+v_s=12 \end{gathered}

Solving the first equation for the velocity of the boat we have:

v_b=8+v_s

Plugging this in the second equation we have:

\begin{gathered} 8+v_s+v_s=12 \\ 2v_s=4 \\ v_s=\frac{4}{2} \\ v_s=2 \end{gathered}

Therefore, the velocity of the stream is 2 m/s

5 0
1 year ago
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