The power delivered to the coil is 721.31 Watts
<h3>How to determine the power</h3>
Given that;
- Power of the heating coil = 500W
- Voltage = 110V
- Diameter of the Nichrome wire = 0. 500mm, radius = 0. 500/2 = 0. 00025m
But the formula for power is given a;
Power, P = V²/R
Then , R = V²/P
R = (110)²/ 500 = 24. 2Ω
To determine the length,
Length, L = RA/ ρ
L = 24. 2 × ( 0. 0025)² × 3. 142/ 10^-6
L = 4. 32m
We also have that;
Resistance, R = Ro( 1 + α ΔT)
R = 24. 2 ( 1 + 0. 0004 × 1180)
R = 35. 62Ω
Current, I = V R
Current, I = 110/24.2 = 4. 5 A
Power delivered = I²R = (4.5)² × 35. 62 = 721.31 Watts
Thus, the power delivered to the coil is 721.31 Watts
Learn more about power here:
brainly.com/question/24858512
#SPJ4
Answer:
1.29 kg
Explanation:
As we know that
W= FS
1.56 = F (0.78)
F= 1.56/0.78
F= 2 N
Now, According to the definition of Force
F= ma
then
m= F /a
m= 2 / 1.54
m = 1.29 kg
Answer:
It doesn't give light
Explanation:
No Flowing of electricity
Visual aids are tools that help to make an issue or lesson clearer or easier to understand and know (pictures, models, charts, maps, videos, slides, real objects etc.). ... Visual aids are those devices which are used in classrooms to encourage students learning process and make it easier and interesting.
