A small smooth object slides from rest down a smooth inclined plane inclined at 30degrees horizontal.What is the acceleration do
1 answer:
You might be interested in
Given that the mass is m = 0.2 kg and the displacement is x = 3 cm = 0.03 m
We have to find the spring constant and potential energy.
The spring constant can be calculated by the formula
Here, k is the spring constant.
g = 9.8 m/s^2 is the acceleration due to gravity.
Substituting the values, the spring constant will be
The potential energy can be calculated as
Answer:
v_{4}= 80.92[m/s] (Heading south)
Explanation:
In order to calculate this problem, we must use the linear moment conservation principle, which tells us that the linear moment is conserved before and after the collision. In this way, we can propose an equation for the solution of the unknown.
ΣPbefore = ΣPafter
where:
P = linear momentum [kg*m/s]
Let's take the southward movement as negative and the northward movement as positive.
where:
m₁ = mass of car 1 = 14650 [kg]
v₁ = velocity of car 1 = 18 [m/s]
m₂ = mass of car 2 = 3825 [kg]
v₂ = velocity of car 2 = 11 [m/s]
v₃ = velocity of car 1 after the collison = 6 [m/s]
v₄ = velocity of car 2 after the collision [m/s]