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ruslelena [56]
4 years ago
15

An electric mixer is used for heat or used for movement?​

Physics
1 answer:
Pavel [41]4 years ago
7 0
Hi i was the time to stop by and then get home from school today haha is a a fun top of my tyyy is the day you get to frost
You might be interested in
A 1500kg car is travelling at v=30m/s. The cars kinetic energy is? *
Anuta_ua [19.1K]

Hi there!

\large\boxed{\text{D. 675000J}}

Use the following formula to solve:

KE = 1/2mv², where:

KE = kinetic energy

m = mass (kg)

v = velocity (m/s)

Therefore:

KE = 1/2(1500)(30)²

KE = 1/2(1500)(900)

KE = 675000 J

4 0
3 years ago
A high intake of alcohol and sugar has little to no real affect on the triglycerides prouction
docker41 [41]
False) high intake of alcohol and sugar increases the triglycerides.
8 0
3 years ago
The position coordinate of a particle which is confined to move along a straight line is given by s =2t3−24t+6, where s is measu
Gre4nikov [31]

Answer:

a) the answer is t=4 seconds

b) acceleration is zero

c) displacement= 142 m

Explanation:

Given the position of the particle

s=2t^3-24t+6

a) the time required when velocity v=72 m/s

v=72=\frac{ds}{st}=6t^2-24

now we solve for time t

6t^2=72+24=96\\\\\implies t^2=\frac{96}{6}\\\therefore t=4 s

b) acceleration when v=30 m/s

acceleration is the time derivative of velocity i.e

a=\frac{dv}{dt}=\frac{d}{dt}(30)=0

c) the net displacement of the particle during the interval t = 1 s to t = 4 s is

s_4-s_1=2t^3-24+6|_{t=4}-2t^3-24+6|_{t=1}\\s_4-s_1=126-(-16)=142 m

7 0
4 years ago
Discuss how the motion of the stunt cyclist relates to the forces acting on the stunt cyclist during the collision
ivolga24 [154]

Answer:

hello your question is incomplete hence I will give you a general answer on how a stunt cyclist performs his stunts successfully

answer ;

The stunt cyclist trying to perform some sort of stunt with the bicycle will be faced with some forces like the static fiction between the tires of the bicycle and wall and also a centripetal force.

In order to overcome the centripetal force the minimal grip of the bicycle must be equal to the weight and the speed at which the cyclist must go can be represented as :

V_{min} = \sqrt{\frac{r.g}{u} }

Explanation:

The stunt cyclist trying to perform some sort of stunt with the bicycle will be faced with some forces like the static fiction between the tires of the bicycle and wall and also a centripetal force.

In order to overcome the centripetal force the minimal grip of the bicycle must be equal to the weight and the speed at which the cyclist must go can be represented as :

V_{min} = \sqrt{\frac{r.g}{u} }

where ; r = radius of the tunnel where the stunt is to be performed

            g = gravitational speed

            u = coefficient of static friction

6 0
3 years ago
Describe the direction in which each object will accelerate. If the object won't accelerate, write "no acceleration." Explain wh
fgiga [73]

Answer:

No acceleration. All of the forces are acting equally on the paper air plane therfore It isn't going to move any where.

5 0
3 years ago
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