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ruslelena [56]
4 years ago
15

An electric mixer is used for heat or used for movement?​

Physics
1 answer:
Pavel [41]4 years ago
7 0
Hi i was the time to stop by and then get home from school today haha is a a fun top of my tyyy is the day you get to frost
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A force of 30 N is applied tangentially to the rim of a solid disk of radius 0.10 m. The disk rotates about an axis through its
den301095 [7]

Answer:

m = 4.0 Kg

Explanation:

  • Using an analogy with the Newton's 2nd law for point masses, for rigid bodies, the external net torque on a rigid body, is equal to its rotational inertia (I), times the angular acceleration (α) of the body, as follows:

       \tau_{ext} = I* \alpha (1)

  • Since the magnitude of the torque is the product of the value of the force times the perpendicular distance between the line of action of  the force and the axis of rotation, and the force is tangential to the rim of the disk, we can write the following expression:

       \tau = F*r*sin 90 = F*r (2)    

  • For a solid disk, the rotational inertia regarding an axis through its center, and perpendicular to its face is as follows:

      I = \frac{m*r^{2}}{2}  (3)

  • Replacing (3) in (1), and (2) in the left side of (1) also, we can solve for m, as follows:

       m = \frac{2*30.0N}{0.1m*150(1/s2)} = 4.0 Kg (4)

  • So, the mass of the disk is 4.0 Kg.
7 0
3 years ago
How does the movement of particles of matter change when matter goes from solid to liquid?
icang [17]
Solid to liquid: molecules spread out to have their own spaces and move energetic and lively.
5 0
3 years ago
Explain quantum zeno effect in one sentence
otez555 [7]
It’s a feature of quantum-mechanical systems allowing a particle's time evolution to be arrested by measuring it frequently enough with respect to some chosen measurement setting.
5 0
3 years ago
Convert <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%280.779mg%29%28min%29%7D%7BL%7D" id="TexFormula1" title="\frac{(0.779mg)(mi
Orlov [11]

The number converted is 0.0467 \frac{(kg)(s)}{m^3}

Explanation:

In order to convert from the original units to the final units, we have to keep in mind the following conversion factors:

1 kg = 1000 g = 10^6 mg

1 min = 60 s

1 m^3 = 1000 L

The original unit that we have is

\frac{mg\cdot min}{L}

Therefore, it can be rewritten as:

=\frac{mg \frac{1}{10^6 mg/kg}\cdot min\cdot  60 s/min}{L\frac{1}{1000L/m^3}}=0.06 \frac{(kg)(s)}{m^3}

Therefore, since the initial number was 0.779, the final value is

0.779\cdot 0.06 \frac{(kg)(s)}{m^3}=0.0467 \frac{(kg)(s)}{m^3}

#LearnwithBrainly

5 0
4 years ago
A driver notices that her 1280 kg car slows down from 92 km/h to 68 km/h in about 7.5 s on the level when it is in neutral. Appr
sweet-ann [11.9K]

Answer:

P = 25299.75 watts

Since 80km/h is the average speed of 92km/h and 68km/h, the power (in watts) is needed to keep the car traveling at a constant 80 km/h is P = 25299.75 watts

Explanation:

Given;

Mass of car m = 1280kg

initial speed v1 = 92km/h = 92×1000/3600 m/s= 25.56m/s

Final speed v2 = 68km/h = 68×1000/3600 m/s= 18.89m/s

time taken t = 7.5s

Change in the kinetic energy of the car within that period;

∆K.E = 1/2 ×mv1^2 - 1/2 × mv2^2

∆K.E = 0.5m(v1^2 -v2^2)

Substituting the values, we have;

∆K.E = 0.5×1280(25.56^2 - 18.89^2)

∆K.E = 189748.16J

Power used during this Change;

Power P = ∆K.E/t

Substituting the values;

P = 189748.16/7.5

P = 25299.75 watts

Since 80km/h is the average speed of 92km/h and 68km/h, the power (in watts) is needed to keep the car traveling at a constant 80 km/h is P = 25299.75 watts

7 0
3 years ago
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