Answer:
d. from the equilibrium position to the bottom and then back to the equilibrium.
g. from the top position to the bottom and then back to the top.
h. from the bottom position to the top and then back to the bottom.
Explanation:
It is the case of SHM or Simple Harmonic Motion. Firstly, there is a need to understand the time interval or time period. The standard definition of time period in simple harmonic motion is
"the time period required for the system to complete its one cycle"
Now one have to consider that the system given above, the motion of mass attached to spring will follow the path of motion from equilibrium point to bottom to equilibrium point to top, then equilibrium point to the bottom and so on.
to choose right answer you must have to consider the option, in which the starting point and ending point of the mass is same. If mass starts from top, the time it will take to reach on top again, will be defined as its time period and so in the case of bottom or equilibrium as starting point. Hence, "d", "g" and "h" are right answers.
Answer:
d = 4180.3m
wavelengt of sound is 0.251m
Explanation:
Given that
frequency of the sound is 5920 Hz
v=1485m/s
t=5.63s
let d represent distance from the vessel to the ocean bottom.
an echo travels a distance equivalent to 2d, that is to and fro after it reflects from the obstacle.
wavelengt of sound is 
= v/f
= (1485)/(5920)
= 0.251 m
Answer:
Vf₂ = 2 Vf₁
It shows that final speed of Joe is twice the final speed of Jim.
Explanation:
First, we analyze the final speed of Jim by using first equation of motion:
Vf₁ = Vi + at
where,
Vf₁ = final speed of Jim
Vi = initial speed of Jim = 0 m/s
a = acceleration of Jim
t = time of acceleration for Jim
Therefore,
Vf₁ = at ---------------- equation (1)
Now, we see the final speed of Joe. For Joe the parameters will become:
Vf = Vf₂
Vi = 0 m/s
a = a
t = 2t
Therefore,
Vf₂ = 2at
using equation (1):
<u>Vf₂ = 2 Vf₁</u>
<u>It shows that final speed of Joe is twice the final speed of Jim.</u>
Answer:
diameter = 9.951 × 
m
Explanation:
given data
NA = 0.1
refractive index = 1.465
wavelength = 1.3 μm
to find out
What is the largest core diameter for which the fiber remains single-mode
solution
we know that for single mode v number is
V ≤ 2.405
and v = 
here r is radius
so we can say
= 2.405
put here value
= 2.405
solve it we get r
r = 4.975979 × 
m
so diameter is = 2 × 4.975979 × m
diameter = 9.951 × m
Yes it does work with the other body system
