What radiation lies at frequencies just below the frequencies of visible light?

1 answer:

3 0

Infrared radiation also called as infrared light was discovered by Sir William Herschel in 1800.It is an electronic magnetic radiation with longer wavelengths than those of a visible light.It involves waves rather than particles. It lies at frequencies just below the frequencies of visible light.

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A block of mass 4 kilograms is initially moving at 5m/s on a horizontal surface. There is friction between the block and the sur

emmasim [6.3K]

• Net vertical force on the block:

∑ F = n - w = 0

(n = magnitude of normal force, w = weight)

n = w = m g

(m = mass, g = 9.8 m/s²)

n = (4 kg) (9.8 m/s²) = 39.2 N

• Net horizontal force:

∑ F = -f = m a

(f = mag. of friction, a = acceleration)

We have f = µ n = 0.5 (39.2 N) = 19.6 N, so

-19.6 N = (4 kg) a

a = -4.9 m/s²

With this acceleration, the block comes to a rest from an initial speed of 5 m/s, so that it travels a distance ∆x in this time such that

0² - (5 m/s)² = 2 (-4.9 m/s²) ∆x

∆x = (25 m²/s²) / (9.8 m/s²) ≈ 2.55 m ≈ 2.6 m

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Imagine a place in the cosmos far from all gravitational and frictional influences. Suppose that you visit that place (just supp

xz_007 [3.2K]

The rock will continue to travel in a straight line with a constant velocity for ever... The reason is, once it leaves your hand there is no force acting on the rock, so it will just continue to move in a natural motion which is constant velocity.

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Diano4ka-milaya [45]

Answer:

Explanation:

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Earth is 149.6 million meters from the Sun and takes 365 days to make one complete revolution around the Sun. Mars is 227.9 mill

luda_lava [24]

Answer:

$\frac{a_{r,earth}}{a_{r,mars}} = 2.325$

Explanation:

The distance of Earth from the Sun is $149.6\times 10^{9}\,m$ and of Mars from the Sun is $227.9\times 10^{9}\,m$ . Let assume that both planets have circular orbits. The centripetal accelaration can be found by using the following expression: