Surface tension and viscosity are used to describe.(circle one)

Andi performs the calculation that is shown below.

rodikova [14]

Answer: 3.59

Explanation:

(2.06)(1.743)(1.00)

2.06 × 1.743 × 1.00

= 3.59058

Two of the multiplied digits are represented in 3 significant figures. Therefore, for correct representation, the result of the product should be written to three significant figures.

3.59058 to 3 significant figures:

First three digits = 3.59

Fourth digit '0' is less than 5, and thus rounded to 0 with other succeeding digits

Therefore, (2.06)(1.743)(1.00) to 3 significant figures equals :

3.59

3 0

3 years ago

Why is 15 m acetic acid an appropriate solvent in which to perform rate studies of electrophilic bromintations?.

Alekssandra [29.7K]

Acetic acid activates the bromine and makes it a better electrophile.

<h3>What is bromination?</h3>

When a substance undergoes bromination, bromine is added to the compound as a result of the chemical reaction. After bromination, the result will have different properties from the initial reactant.

<h3>Why is 15M acetic acid used as a solvent for bromination?</h3>

DCM (dichloromethane) requires more time. Acetic acid has protons that can give one of the Br (bromine) a positive charge and activate it. There is a brief loss of aromaticity that calls for high energy activation.

Refer to the attached image for bromination reaction.

Learn more about bromination here:

brainly.com/question/26428023

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8 0

1 year ago

Read 2 more answers

When 4.15 grams of silver nitrate is reacted with 1.11 grams of iron(III) chloride, which best represents the amount of silver c

PolarNik [594]

Answer:

The mass of silver chloride produced = 2.202 g

Explanation:

Equation of the reaction is given below

3AgNO₃(aq) + FeCl₃(aq) ----> 3AgCl(s) + Fe(NO₃)₃(aq)

molar mass of AgNO₃ = 170 g/mol

molar mass of FeCl₃ = 233.5 g/mol

molar mass of AgCl = 143.5 g/mol

3 moles of silver nitrate reacts with 1 mole of iron (iii) chloride to give 3 moles of silver nitrate

4.15 grams of AgNO₃ = 4.15/170 = 0.0244 moles of AgNO₃

1.11 grams of FeCl₃ = 1.11/233.5 = 0.0047 moles of FeCl₃

mole ratio of AgNO₃ to FeCl₃ = 0.0244/0.0047 = 5 : 1

therefore, FeCl₃ is the limiting reactant

0.0047 moles of FeCl₃ reacting will produce 0.0047 * 3 moles of AgCl = 0.0141 moles of AgCl

0.0141 moles of AgCl = 0.0141 * 143.5 g of AgCl = 2.02 g of AgCl =

Therefore mass of silver chloride produced = 2.202 g

3 0

3 years ago

Barium sulfate is made by the following reaction.

ipn [44]

Answer:

%age Yield = 96 %

Explanation:

The balance chemical equation for given double replacement reaction is,

Ba(NO₃)₂ + Na₂SO₄ → BaSO₄ + 2 NaNO₃

Step 1: <u>Calculate moles of Ba(NO₃)₂:</u>

Moles = Mass / M.Mass

Moles = 75.1 g / 261.33 g/mol

Moles = 0.2873 moles of Ba(NO₃)₂

Step 2: <u>Find out moles of BaSO₄ formed:</u>

According to balance chemical equation,

1 mole of Ba(NO₃)₂ produced = 1 mole of BaSO₄

So,

0.2873 moles of Ba(NO₃)₂ will produce = X moles of BaSO₄

Solving for X,

X = 0.2873 mol × 1 mol / 1 mol

X = 0.2873 moles of BaSO₄

Step 3: Calculate Theoretical Mass of BaSO₄:

Mass = Moles × M.Mass

Mass = 0.2873 mol × 233.38 g/mol

Mass = 67.07 g of BaSO₄

Step 4: <u>Calculate %age Yield as:</u>

Theoretical Yield = 67.07 g

Actual Yield = 64.4 g

%age Yield = <u>???</u>

Formula Used:

%age Yield = (Actual Yield ÷ Theoretical Yield) × 100

Putting Values,

%age Yield = (64.4 g ÷ 67.07 g) × 100

%age Yield = 96.01 % ≈ 96 %

6 0

3 years ago

What is the concentration of a solution with a volume of 2.5 liters containing 600 grams of calcium phosphate?

trapecia [35]

Answer:

1.12M

Explanation:

Given parameters:

Volume of solution = 2.5L

Mass of Calcium phosphate = 600g

Unknown:

Concentration = ?

Solution:

Concentration is the number of moles of solute in a particular solution.

Now, we find the number of moles of the calcium phosphate from the given mass;

Formula of calcium phosphate = Ca₃PO₄

molar mass = 3(40) + 31 + 4(16) = 215g/mol

Number of moles of Ca₃PO₄ = $\frac{600}{215}$ = 2.79moles

Now;

Concentration = $\frac{Number of moles }{volume }$

Concentration = $\frac{2.79}{2.5}$ = 1.12M

7 0

3 years ago