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FinnZ [79.3K]
3 years ago
9

If I start with 5 grams of c3h8 what is my theoretical yield of water

Chemistry
1 answer:
Triss [41]3 years ago
5 0
C3H8  (propane) undergoes   combustion  to   produce  water  and  carbon (IV)  oxide  according  to   equation   below
C3H8(g)  +  5 O2(g)  ---->  3 CO2(g)  +  4 H2O(l)

calculate  the  moles  of  C3H8  used
mole =  mass/molar  mass
molar  mass  of  C3H8  = ( 12x3  )+(  1  x  8)=44  g/mol
moles  of  C3H8=  5g/  44 g/mol=  0.114  moles
by  use    of  mole  ratio  between  C3H8  to H2O   which  is  1:4  therefore  the  mole  of  water=  0.114  x4=0.456  moles
mass  of  water  =moles  of  water  x molar  mass  of  water

that  is  0.456 moles  x  18g/mol  = 8.208  grams
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Explanation:

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34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases
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Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

<em>Where q is heat of reaction in J,</em>

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The mass of the solution is obtained from the volume and the density as follows:

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Automotive airbags inflate when a sample of sodium azide, NaN3, is very rapidly decomposed.
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The molar mass of N₂ is 28.01 g/mol.

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Step 3: Calculate the moles of NaN₃ needed to form 3.42 moles of N₂

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Step 4: Calculate the mass corresponding to 2.28 moles of NaN₃

The molar mass of NaN₃ is 65.01 g/mol.

2.28 mol × 65.01 g/mol = 148 g

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2 years ago
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