5 grams of NaHCO3 was added to 50 cm3 of 1.5 mol dm-3 hydrochloric acid, causing the temperature to decrease by 6.8 K. What is t
2 answers:
The chemical equation representing the neutralization reaction between HCl and is,
Given mass of = 5g
Moles of =
Volume of HCl solution =
Assuming the density of solution to be 1.0 g/mL
Mass of HCl solution = 50 g
Total mass of solution = 50 g+ 5 g = 55 g
Calculating the heat of neutralization:
Q = m C ΔT
m is mass of solution = 55 g
C is the specific heat capacity of the solution = 4.184
ΔT = Temperature difference = 6.8 K = (6.8 -273 ) C = -266.2
Enthalpy of neutralization per mole of
=
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