The differnce of 2 perfect cubes
remember
a³-b³=(a-b)(a²+ab+b²)
so
remember
a³-b³=(a-b)(a²+ab+b²)
so
If f(x) = 2x^3– 5x+ 2, then what is the remainder when f(x) is divided by X – 4?
1 answer:
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To calculate minimum value, do -b/2a to get the x-value, and plug it in to get the y-value:
-6/8 = -3/4
So the minimum value of g(x) is -81/4
This shows that g(x) has a lesser minimum value than f(x)
-6/8 = -3/4
So the minimum value of g(x) is -81/4
This shows that g(x) has a lesser minimum value than f(x)
Sorry didn't know how to write the answer so I just took a screen shot of my answer for you!
