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Xelga [282]
3 years ago
15

When a 49 pound weight is attached to the spring, the spring stretches 7 inches. Assume that the length of the spring y varies d

irectly with the weight attached x. write and solve a direct variation equation to find the length of the spring when a 63 pound weight is attached
solution please :)
Mathematics
1 answer:
stealth61 [152]3 years ago
8 0
I'm not totally sure, but it might be y= x/7.
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Read 2 more answers
PLEASE HELP WILL GIVE BRAINLIEST.
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Answer:

Choice D

Step-by-step explanation:

For this one I would find if the point lands on the line.

<em><u>Choice A:</u></em>

What we have to do is to plug in -4 for x and 4 for y.

y=2x+10\\(4)=2(-4)+10\\4=-8+10\\4\ne2

The point is not on this line so this cannot be it.

<em><u>Choice B:</u></em>

We pug what we know again.

y=\frac{1}{3}x+1\\(4)=\frac{1}{3}(-4)+1\\(4)=-\frac{4}{3}+1\\4\ne-\frac{1}{3}

The point is not on this line so it can't be it.

<em><u>Choice C:</u></em>

We pug in what we know again.

y=3x-9\\(4)=3(-4)-9\\(4)=-12-9\\4\ne-21

The point is not on this line so it can't be it.

The next one has to be it, but we'll check it just in case.

<em><u>Choice D:</u></em>

We plug in what we know again.

y= \frac{1}{2}x+6\\(4)=\frac{1}{2}(-4)+6\\(4)=-2+6\\4=4

The point is on this line so this is the line.

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