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brilliants [131]
3 years ago
14

How many grams of silver oxide are needed to react with 7.9 g of hydrochloric acid produce silver chloide and water?

Chemistry
1 answer:
Anastaziya [24]3 years ago
7 0

Answer:

25.11 g.

Explanation:

  • It is clear from the balanced equation:

<em>Ag₂O + 2HCl → 2AgCl + H₂O.</em>

<em></em>

that 1.0  mole of Ag₂O reacts with 2.0 moles of HCl to produce 2.0 mole of AgCl and 1.0 moles of H₂O.

  • 7.8 g of HCl reacts with excess Ag₂O. To calculate the no. of grams of Ag₂O that reacted, we should calculate the no. of moles of HCl:

<em>no. of moles of HCl = mass/atomic mass</em> = (7.9 g)/(36.46 g/mol) = <em>0.2167 mol.</em>

  • From the balanced equation; every 1.0 mol of Ag₂O reacts with 2 moles of HCl.

∴ 0.2167 mol of HCl will react with (0.2617 mol / 2 = 0.1083 mol) of Ag₂O.

<em>∴ The mass of reacted Ag₂O = no. of moles x molar mas</em>s = (0.1083 mol)(231.735 g/mol) = <em>25.11 g.</em>

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