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2 years ago

How would you prepare the following aqueous solutions?

Chemistry

1 answer:

Xelga [282]2 years ago

6 0

The molarity of the solution is 0.1625M.

<h3>What do you meant by Molarity</h3>

Molarity is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of solute per litres of a solution .

Molarity → no of moles / Volume (L)

SI unit of Molarity is M or mol/ L

We have given here the mass of solution is 3.10×10²g .

molality of the solution is 0.125m

Molality → no of moles / mass in kg

→ 0.125×3.10×10²/ 1000

→ no.of moles = 0.0162

For molarity we can assume volume as 1000 ml .

Molarity = 0.0162×1000/ 100

Molarity →0.162 M.

So, the molarity of solution will be 0.162M.

to Learn more about Molarity click here brainly.com/question/8732513

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<h3>Carbon atoms</h3>

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3 years ago

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Answer: The empirical formula for the given compound is $CH_2$

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The chemical equation for the combustion of compound having carbon and hydrogen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

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We know that:

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In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, $\frac{12}{44}\times 22.0=6g$ of carbon will be contained.

For calculating the mass of hydrogen:

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To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = $\frac{0.5}{0.5}=1$

For Hydrogen = $\frac{1.0}{0.5}=2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is $C_{1}H_{2}=CH_2$

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