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3 years ago

What is a group in the periodic table of elements?

Chemistry

2 answers:

chubhunter [2.5K]3 years ago

3 0

Answer:

B. The elements that have similar densities and atomic sizes

Explanation:

xeze [42]3 years ago

3 0

Answer:

carbon

Explanation:

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How many molecules are in 3.8 mols of copper?

ioda

Answer:

Hi there!

The correct answer is 2.29 x $10^{24}$ molecules

Explanation:

To convert from the moles to molecules:

1 mole = 6.022 x 10²³ molecules

so basically you multiply 3.8 by 6.022 x 10²³

and you get: 2.29 x $10^{24}$

5 0

4 years ago

9. Determine the number of protons, neutrons, and electrons in one 'H' ion. Explain how you found your

Katyanochek1 [597]

Answer:

'H' ion has only one proton and do not have any electron and neutron.

Explanation:

Hydrogen atom has only one electron and one proton and when it loses that electron, hydrogen ion (H+) is formed which is positively charged (charge of +1) and referred as a proton.

So, hydrogen ion do not left with any electrons or have zero electrons.

Hydrogen (H) atom do not have any neutrons in its tiny nucleus, so hydrogen ion (H+) also do not have neutrons.

Hence, 'H' ion (H+) has only proton and zero electron and neutron.

4 0

3 years ago

What do melted ice cooling lava and boiling water have in common?

KIM [24]

They are all transioning in states of matter

7 0

4 years ago

I WILL MARK THE BRAINLYEST AND GIVE YOU 100 POINTS

yuradex [85]

4 moles

64 grams of oxygen contains 4 moles

3 0

3 years ago

Read 2 more answers

If only 0.186 g of Ca(OH)2 dissolves in enough water to give 0.230 L of aqueous solution at a given temperature, what is the Ksp

Lilit [14]

Answer:

$Ksp=5.20x10^{-6}$

Explanation:

Hello there!

In this case, according to the solubility equilibrium of calcium hydroxide:

$Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-$

Whereas the equilibrium expression is:

$Ksp=[Ca^{2+}][OH^-]^2$

It is firstly necessary to calculate the molar solubility given the grams and volume of the dissolved solute:

$s=\frac{0.186g/(74.09g/mol)}{0.230L}=0.0109M$

Now, according to the Ksp expression, we plug in s as the solubility to obtain:

$Ksp=(s)(2s)^2\\\\Ksp=(0.109)(2*0.0109)^2\\\\Ksp=5.20x10^{-6}$

Regards!

8 0

3 years ago