Mean = 62 in
SD = 2 in
At 16% = 0.16 and using Z tables,
Z≈ -0.99
x =(-0.99*2) + 62 ≈ 60 in
This represents jockeys who are shorter than 60 in.
Part A:
The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

Given that the average precipitation in
Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

Part B:
</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and
standard deviation, σ is greater than a given value, a is given by:

Given that the average precipitation in
Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:
</span>
Answer: 4.1 inches
Step-by-step explanation:
From the question, we are informed that New York City is approximately 205 miles from Washington, D.C.
The distance that these cities will appear on a map with the scale 1 in: 50 miles will be represented by x.
Therefore, x:205 = 1:50
Cross multiply
x/205 = 1/50
50x = 205
x = 205/50
x = 4.1 inches
The answer is 4.1 inches
The discount is $7.5 if the discount is what you are looking for.
$50 - $42.50 is $7.5
If you are looking for a percentage then the answer is 85%