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Answer:
The element iodine forms an anion with the charge -1. The symbol for this ion is I⁻¹, and the name is iodide. The number of electrons in this ion is 7.
Explanation:
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In this case, we have to consider iodine has the capacity to accept the electrons lost by other elements such as metals or hydrogen by becoming negatively charged. Such phenomena makes iodine to form an anion (negatively charged) with the charge -1, since it only needs one electron to attain the octet. Moreover, the symbol of such ion is I⁻¹ and its name is iodide. By cause of the aforementioned, the number of electrons it has is 7 since at its outer shell seven electrons are found (see electron configuration Kr,5s²,5p⁵).
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You can simply subtract the atomic number from the mass number in order to find the number of neutrons.
Neon has a smaller atomic radius do it having less of an electron shield. Also the more protons an element has the tighter it is held together making it smaller.
Answer:
Chemical Equation Balancer C15H31COOH+NaOH = C15H31COONa+H20
Explanation:
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