Answer:
C21H2802
Explanation:
C=12g/mol
H=1g/mol
O=16g/mol
Part (C) of compound-80.18%
(0.8018 x 312)/12=21
Part (H) of compound-8.97%
(0.897 x 312)/1=28
Part (O) of compund-10.3%
(0.103 x 312)/16 = 2
Therefore the emp. formula is C12H28O2
The equation that shows the formation of chromium (ii) ion from neutral chromium atom is as follow
Cr ---> cr^2+ + 2e-
Cr^2+ is the chromium ion with oxidation state of two which is one of the common ion of chromium. Other common ion of chromium include chromium of oxidation state 6 and 3
<span>Carbon-6, Hydrogen-12, Oxygen-6
Number of atoms altogether: 24</span>
Answer:
The Answer is : A
Explanation:
Im taking the exam right now lol
Answer:
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Explanation:
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