I’m pretty sure it’s Nose
A electrochemical reaction is said to be spontaneous, if
Answer 1:
Consider reaction: <span>Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)
The cell representation of above reaction is given by;
</span>
![S^{2-}/S // Ni^{2+}/Ni](https://tex.z-dn.net/?f=%20S%5E%7B2-%7D%2FS%20%2F%2F%20%20Ni%5E%7B2%2B%7D%2FNi%20%20)
Hence,
![E^{0}cell = E^{0} Ni^{2+/Ni} - E^{0} S/S^{2-}](https://tex.z-dn.net/?f=%20E%5E%7B0%7Dcell%20%3D%20%20E%5E%7B0%7D%20Ni%5E%7B2%2B%2FNi%7D%20-%20%20E%5E%7B0%7D%20S%2FS%5E%7B2-%7D%20%20%20%20%20)
we know that,
![{E^{0} Ni^{2+}/Ni = -0.25 v](https://tex.z-dn.net/?f=%7BE%5E%7B0%7D%20Ni%5E%7B2%2B%7D%2FNi%20%20%3D%20-0.25%20v%20%20%20%20%20%20)
and
![{E^{0} S/ S^{2-} = -0.47 v](https://tex.z-dn.net/?f=%7BE%5E%7B0%7D%20S%2F%20S%5E%7B2-%7D%20%20%3D%20-0.47%20v%20)
Therefore,
![E^{0} cell](https://tex.z-dn.net/?f=E%5E%7B0%7D%20cell%20)
= - 0.25 - (-0.47) = 0.22 v
Since,
is positive, hence cell reaction is spontaneous
.....................................................................................................................
Answer 2: Consider reaction: <span>Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)
</span>
The cell representation of above reaction is given by;
![H_{2} / H^{+} // Pb^{2+} /Pb](https://tex.z-dn.net/?f=H_%7B2%7D%20%2F%20%20H%5E%7B%2B%7D%20%2F%2F%20%20Pb%5E%7B2%2B%7D%20%2FPb)
Hence,
![E^{0}cell = E^{0} Pb/Pb^{2+} - E^{0} H_{2}/H^{+}](https://tex.z-dn.net/?f=%20E%5E%7B0%7Dcell%20%3D%20E%5E%7B0%7D%20Pb%2FPb%5E%7B2%2B%7D%20-%20E%5E%7B0%7D%20H_%7B2%7D%2FH%5E%7B%2B%7D%20)
we know that,
![{E^{0} Pb^{2+}/Pb = -0.126 v](https://tex.z-dn.net/?f=%7BE%5E%7B0%7D%20Pb%5E%7B2%2B%7D%2FPb%20%3D%20-0.126%20v%20)
and
![{E^{0} H_{2}/ H^{+} = -0 v](https://tex.z-dn.net/?f=%7BE%5E%7B0%7D%20H_%7B2%7D%2F%20H%5E%7B%2B%7D%20%3D%20-0%20v%20)
Therefore,
![E^{0} cell](https://tex.z-dn.net/?f=E%5E%7B0%7D%20cell%20)
= - 0.126 - 0 = -0.126 v
Since,
is negative, hence cell reaction is non-spontaneous.....................................................................................................................
Answer 3:
Consider reaction: <span>2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)
</span>
The cell representation of above reaction is given by;
![Cr/Cr^{2+} // Ag^{+}/Ag](https://tex.z-dn.net/?f=%20Cr%2FCr%5E%7B2%2B%7D%20%2F%2F%20Ag%5E%7B%2B%7D%2FAg%20)
Hence,
![E^{0}cell = E^{0} Ag^{+}/Ag - E^{0} Cr/Cr^{2+}](https://tex.z-dn.net/?f=%20E%5E%7B0%7Dcell%20%3D%20E%5E%7B0%7D%20Ag%5E%7B%2B%7D%2FAg%20-%20E%5E%7B0%7D%20Cr%2FCr%5E%7B2%2B%7D%20)
we know that,
![{E^{0} Ag^{+}/Ag = -0.22 v](https://tex.z-dn.net/?f=%7BE%5E%7B0%7D%20Ag%5E%7B%2B%7D%2FAg%20%3D%20-0.22%20v%20)
and
![{E^{0} Cr/ Cr^{2+} = -0.913 v](https://tex.z-dn.net/?f=%7BE%5E%7B0%7D%20Cr%2F%20Cr%5E%7B2%2B%7D%20%3D%20-0.913%20v%20)
Therefore,
![E^{0} cell](https://tex.z-dn.net/?f=E%5E%7B0%7D%20cell%20)
= - 0.22 - (-0.913) = 0.693 v
Since,
is positive, hence cell reaction is spontaneous
Answer: Electromagnetic waves are transverse in nature as they propagate by varying the electric and magnetic fields such that the two fields are perpendicular to each other.
Accelerated charges are responsible to produce electromagnetic waves.
Explanation:
What’s wrong? ...........:.........