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Zepler [3.9K]
4 years ago
7

How many moles of carbon dioxide, co2, are produced if 5.87 moles of glucose, c6h12o6, react?

Chemistry
1 answer:
almond37 [142]4 years ago
3 0
The balanced equation for the reaction is as follows
C₆H₁₂O₆ + 6O₃ --> 6CO₂ + 6H₂O
stoichiometry of glucose to CO₂ is 1:6
when 1 mol of glucose reacts - 6 mol of CO₂ are formed 
therefore when 5.87 mol of glucose reacts - 6 x 5.87 mol = 35.22 mol
therefore 35.2 mol of CO₂ is formed 
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A solution is made by mixing of water and of acetic acid . Calculate the mole fraction of water in this solution. Be sure your a
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please find the complete question in the attached file.

Mass of CH_3C0_2 H= 77 \ g \\\\

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No of moles in n_{CH_3CO_2H} = 77 \ g \times  \frac{1 \ mol \ CH_3C0_2H}{60.05 \ g}  

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= 42 \ g \times \frac{1 mol H_2O}{18.02 \ g} \\\\= 2.33 \ mol \ H_2 O

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X CH_2CO_2H = \frac{n_{CH_3CO_2H}}{n_CH_3CO_2H +n_{H_2}}\\\\

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