A rate often involves time: e. g., 33 feet per second; also, we are finding the ratio of one type of measurement with respect to another: distance and time.
A proportion is often the ratio of different measures of the same thing:
e. g. 5 apples
------------
7 apples
Answer:
Please check the explanation.
Step-by-step explanation:
- As we know that the values in the table represent a function only if there there is only 1 input for every output.
Given the table 1
x y
-12 2
-10 10
0 -2
5 -6
8 -11
15 -15
From the table, it is clear that for each input there exists a unique output.
i.e.
According to the given table,
y = 2 at x=-12
y = 10 at x=-1
0
y = -1 at x=0
y = -11 at x=8
y = -15 at x=15
From the table, it is clear that for each input x, it has a unique output y.
Hence, table 1 is a function.
Given the table 2
x y
9 -18
-20 0
-6 1
-17 16
9 17
11 19
This table does not produce a function, because the input x=9 produces two outputs.
i.e.
at x = 9, the y = -18
at x = 9, the y = 17
Therefore, the table 2 does not represent a function.
First, you must find the side length. It is a hexagon so there are 6 sides. You take the perimeter by 6 48/6 and get 8. Then plug it into formula (3 sqrt 3)/2 a^2 where a is side length. Plug into formula and get an answer of 166.28 in^2
Answer:
- time = 1second
- maximum height = 16m
Step-by-step explanation:
Given the height of a pumpkin t seconds after it is launched from a catapult modelled by the equation
f(t)=-16t²+32t... (1)
The pumpkin reaches its maximum height when the velocity is zero.
Velocity = {d(f(x)}/dt = -32t+32
Since v = 0m/s (at maximum height)
-32t+32 = 0
-32t = -32
t = -32/-32
t = 1sec
The pumpkin reaches its maximum height after 1second.
Maximum height of the pumpkin is gotten by substituting t = 1sec into equation (1)
f(1) = -16(1)²+32(1)
f(1) = -16+32
f(1) = 16m
The maximum height of the pumpkin is 16m
Answer:
Determination of HYP,OPP,ADJ with respect to x.
<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>right</u><u> </u><u>angle</u><u>:</u><u>Hypotenuse</u><u>:</u><u> </u><u>AC</u>
<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>given</u><u> </u><u>angle</u><u>:</u><u> </u><u>Opp</u><u>:</u><u>BC</u>
<u>remaining</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u>:</u><u> </u><u>Adjacent</u><u>:</u><u>AB</u><u>.</u>