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Nonamiya [84]
3 years ago
14

The graph of the function f(x) = log5 (x) is stretched vertically by a factor of 2, shifted to the left by 8 units, and shifted

up
by 3 units.
Find the equation of the function g(x) described above.

Mathematics
1 answer:
atroni [7]3 years ago
7 0

Answer:

We start with y = g(x) = f(x)

First, we have a vertical stretch by a factor of 2.

A vertical strech by a factor of A will be g(x) = A*f(x)

then in this case A = 2, so we have g(x) =  2*f(x)

Now we have it shifted left by 8 units.

We know that f(x - A) shift right the graph by A units (A positive), here A = 8.

then we have: g(x) =  2*f(x - 8)

Now we want shift up 3 units, if we have y = f(x) we can shift the graph up by A units as: y = g(x) + A (for A positive)

Then we have: g(x) =  2*f(x - 8) + 3

now, our function was f(x) = Log₅(x)

then g(x) = 2*log₅(x - 8) + 3.

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<u>Part 1</u>

<u />(f\circ g)(x)=f(\sqrt{x})=4\sqrt{x}+1

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus, the domain is \boxed{[0, \infty)}

<u>Part 2</u>

<u />(g \circ f)(x)=g(4x+1)=\sqrt{4x+1}

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus,

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Thus, the domain in interval notation is \boxed{\left[-\frac{1}{4}, \infty)}

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Schach [20]

The area of the semicircle is A = 1187.9 cm².

<h3>What is the area of a circle?</h3>

The area of a circle with a radius of r is A = πr².

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