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marshall27 [118]
3 years ago
11

What are 3 ways to solve a system of linear equations?​

Mathematics
1 answer:
ANEK [815]3 years ago
7 0
The three ways are substitution, elimination, and graphing
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How To Solve these? ​
Inessa [10]

Answer:

a. 15/23

b. 13/27

c. 400g

Step-by-step explanation:

a. When the denominators are the same, you can just sum the numerators.

Which becomes, 13+2=15--> 15/23

b. Same, when the denominator is the same, you can just minus the numerators. Which becomes, 25-12=13--> 13/27

c. 1kg=1000g. 1000/5=200✖️2=400

5 0
3 years ago
Write an equation in point-slope form and slope-intercept form for
slava [35]

Answer:

point slope: y-7=2(x-4

slope intercept: y=2x-1

Step-by-step explanation:

point slope form: y-y1=m(x-x1)

(4,7) and m=2

using all the info here is it in point slope form: <u>y-7=2(x-4)</u>

turning the point slope equation into slope intercept...

slope intercept form: y=mx+b

first simplify y-7=2(x-4) into y-7=2x-8

then add 7 to both sides...

which would be <u>y=2x-1 </u>

and thats your answer!!

4 0
3 years ago
Solve the system of equations. y = x + 2, y = x2 + 7x + 10
Monica [59]

Answer:

(- 2, 0 ) and (- 4, - 2 )

Step-by-step explanation:

Given the 2 equations

y = x + 2 → (1)

y = x² + 7x + 10 → (2)

Since both equations express y in terms of x we can equate them, that is

x² + 7x + 10 = x + 2 ( subtract x + 2 from both sides )

x² + 6x + 8 = 0 ← in standard form

(x + 2)(x + 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x + 4 = 0 ⇒ x = - 4

Substitute these values into (1) for corresponding values of y

x = - 2 : y = - 2 + 2 = 0 ⇒ (- 2, 0 )

x = - 4 : y = - 4 + 2 = - 2 ⇒ (- 4, - 2 )

Solutions are (- 2, 0 ) and (- 4, - 2 )

5 0
3 years ago
I need an equation: the cost of a liter of soda is $0.53 less than twice the cost of a gallon of water if the cost of a liter of
LenaWriter [7]

2(1.25 + .53) = g
3 0
3 years ago
I ONLY need 8c<br> Please show ALL STEPS
viktelen [127]

Answer:

8c

f(g(x)) = x^4 + 2x^3 - x

g(f(x)) =  x^4 + 2x^3 + 2x^2 - x

Step-by-step explanation:

f(x) = x^2 - x ; g(x) = x^2 + x

f(g(x)) = (x^2 + x)^2 - (x^2 + x)

f(g(x)) = (x^2 + x)^2 - x^2 - x

f(g(x)) = (x^2 + x)(x^2 + x) - x^2 - x

f(g(x)) = x^4 + x^3 + x^3 + x^2 - x^2 - x

f(g(x)) = x^4 + 2x^3 - x

g(f(x)) = (x^2 - x)^2 + x^2 - x

g(f(x)) = (x^2 + x)(x^2 + x) + x^2 - x

g(f(x)) = x^4 + x^3 + x^3 + x^2 + x^2 - x

g(f(x)) =  x^4 + 2x^3 + 2x^2 - x

3 0
3 years ago
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