1. Find the perimeter of the triangle with coordinates A (1, 2), B( 6, 5), and C (1, 7)
1 answer:
The perimeter is just the sum of all side lengths. Here we have sides AB, BC, and AC.
The side lengths are found using the pythagorean theorem...
d^2=(dx)^2+(dy)^2
AB^2=5^2+3^2=34, AB=√34
BC^2=5^2+2^2=29, BC=√29
AC^2=0^2+5^2=25, AC=√25
So the perimeter is:
P=√34+√29+√25
P≈16.22 units (to the nearest hundredth of a unit)
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