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2 years ago

Refer to your Expeditions in Reading book for a complete version of this text.

Mathematics

1 answer:

ahrayia [7]2 years ago

6 0

Answer:

The 3rd one, The 1st one and The last one.

Step-by-step explanation:

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Grace drew a triangle with sides of equal length. Its measured with sides of 3 cm. What is the perimeter of the triangle?

Otrada [13]

Answer:

9 cm explained to

Step-by-step explanation:

explained that

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3 years ago

BigorU [14]

Yup here you go it’s uhmmmm idk anymore heheh

6 0

3 years ago

PLEASE HELP

Ronch [10]

Answer:

1 and 5

Step-by-step explanation:

The squares have a side length of 10 and 1 square side is the radius of the half-circles. Since there are two half-circles, find the circumference for one full circle:

$C=2\pi r$

Insert the radius:

$r=10\\C=2\pi *10$

Simplify pi:

$C=2*3.14*10$

Simplify multiplication:

$C=6.28*10\\C=62.8$

The circumference of the circles is 62.8. Now find the perimeter of the exposed squares with side length 10. There are 4 exposed sides, which equals one square. Find the perimeter:

$P=10+10+10+10\\P=10+10+20\\P=10+30\\P=40$

Add the perimeter of the circle and the square together:

$P=62.8+40=102.8$

Now see which of the options gives you the perimeter:

1. $40+20\pi =102.8$ ****

2. $unavailable$

3. $120+20\pi =182.8$

4. $300+100\pi =614.2$

5. $10+10+10\pi +10+10+10\pi =102.8$ ****

Finito.

7 0

3 years ago

M3+ 3 m3 + 4 m² simplify

Kipish [7]

Answer:

${m}^{3} + {27}^{m} + 4 {m}^{2}$

Step-by-step explanation:

${m}^{3} + {3}^{m 3} + 4 {m}^{2}$

${m}^{3} + {3}^{m \times 3} + 4 {m}^{2}$

${m}^{3} + {3}^{3m} + 4 {m}^{2}$

${3}^{3m} = ({3}^{3} {)}^{m} = {27}^{m}$

➡️ ${m}^{3} + {27}^{m} + 4 {m}^{2}$

5 0

3 years ago

Plz help with the whole page plz

arlik [135]

To Work Out Questions Like The First One That Reads : 3/10 Of 250, All You Have To Do Is Simply Divide 250 By The Denominator, Which Is 10 In This Case And The Multiply It By The Numerator (3). Answer ~ 250 Divided By 10 = 25 X 3 = 75 I Hope That Helps, And If You Are Stuck Of Any Other Types Of These Questions, Feel Free To Ask Me

3 0

3 years ago