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nadya68 [22]
4 years ago
10

A component of a circuit changes, as shown below. At left a short horizontal line then a small circle with a line pointing up at

about 45 degrees then a short gap then a small circle then a short horizontal line. In the middle an arrow pointing right. At right a short horizontal line then a small circle then a shorter horizontal line then a small circle then a short horizontal line. How would this change affect the electric circuit? A switch is closed, so the circuit would be incomplete and broken and the lights in the circuit would not shine. A switch is closed, so the circuit would be complete and unbroken and the lights in the circuit would shine. A switch is opened, so the circuit would be incomplete and broken and the lights in the circuit would not shine. A switch is opened, so the circuit would be complete and unbroken and the lights in the circuit would shine.
Biology
2 answers:
Afina-wow [57]4 years ago
8 0

Answer:

B A switch is closed, so the circuit would be complete and unbroken and the lights in the circuit would shine.

Explanation:

LiRa [457]4 years ago
6 0

Answer:

A switch is closed, so the circuit would be complete and unbroken and the lights in the circuit would shine.

Explanation:

just took the test got 100

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A genetic cross with two genes produces 400 offspring, and 20 of them have recombinant phenotypes. What is the recombination fre
sp2606 [1]

Linkage refers to the tendency of inhertance of the DNA sequences that are close together on a chromosome during the meiosis of sexual reproduction. It can be measured by the recombination frequency.

Recombination frequency describes the proportion of recombinant offsrpring produced in a genetic cross between two organisms. It is the frequency with which a single chromosomal cross over takesplace between two genes during the process of meiosis. Recombination frequency (RF) is given by

RF= Recombinants /total offspring  x 100.

In the above example, the number of recombinant offspring is 20 and the total offspring is 400. By substituting these values,

RF= 20/400 x100

= 5.

The recombination frequency for the above cross is 5.


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