:
change in potential energy , ∆Ep = 156.8Joules
Explanation:
Given;
Mass of object , m = 2.0 kg
Heights ; h₂ = 5.0m
h₁ = - 3.0m
To obtain
the change in potential energy, ∆Ep = ?
But,
∆Ep = mg∆h
Where;
m is the mass of the object (kg)
∆h = h₂ - h₁ is the change in height (m)
g is the acceleration due to gravity ( 9.80 m/s²)
Therefore,
the change in potential energy, ∆Ep = 2.0 × 9.80 × ( 5 - (- 3))
=156.8 joules
Let x = the angle of elevation for shooting the arrow.
Assume
g = 9.8 m/s²
No wind resistance
The vertical launch velocity is 25.1 sin(x) m/s
The horizontal velocity is 25.1 cos(x) m/s
The time of flight is
24/[25.1 cos(x)] s = 0.9562 sec(x) s
Therefore
0.5*[0.9562 sec(x)]*(9.8) = 25.1 sin(x)
4.6854 = 25.1* sin(x)cos(x)
sin(2x) = 0.3733
2x = sin⁻¹ 0.3733 = 21.92 deg
x = 10.96 deg
Answer: 11 degrees (nearest integer)
Answer:
W = 819152 J = 819.15 KJ
Explanation:
The work done by Juri can be given by the following formula:
where,
W = Work done = ?
F = Force = 200 N
d = distance = 5 km = 5000 m
θ = angle to horizontal = 35°
Therefore,
W = (200 N)(5000 m)Cos 35°
<u>W = 819152 J = 819.15 KJ</u>
Answer:
The value of the effective (rms) voltage of the applied source in the circuit is 132 V
Explanation:
Given;
effective (rms) voltage of the resistor, 
= 65 V
effective (rms) voltage of the inductor, 
= 140 V
effective (rms) voltage of the capacitor, 
= 80 V
Determine the value of the effective (rms) voltage of the applied source in the circuit;
Therefore, the value of the effective (rms) voltage of the applied source in the circuit is 132 V.
Answer:
b. Both the gratings will produce the same separation of peaks.
e. The grating with 10 slits will produce better-defined(narrower) peaks.
