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Maslowich
3 years ago
14

Under which condition would time periods of daylight and darkness be equal everywhere on Earth all year? A. if Earth revolved ar

ound the sun in a more circular orbit B. if Earth rotated on an axis that was not tilted with respect to Earth's orbit C. if Earth had two moons D. if Earth revolved in an orbit closer to the sun
Physics
2 answers:
FromTheMoon [43]3 years ago
8 0
The answer is b because that is the correct one
Alecsey [184]3 years ago
3 0
I guess it is B as it is more relevant to reality and also the duration of the day is independent off the others.
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The United States and South Korean soccer teams are playing in the first round of the World Cup. An American kicks the ball, giv
garik1379 [7]

Answer:

Vf = 3.67 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f} ^{2} =v_{i} ^{2} -(2*a*x)

where:

Vf = final velocity [m/s]

Vi = initial velocity = 4.3 [m/s]

a = acceleration or desacceleration = 0.5 [m/s²]

x = distance = 5 [m]

Note: The negative sign in the above equation means that the velocity of the ball is decreasing (desacceleration).

Now replacing:

Vf² = (4.3)² - (2*0.5*5)

Vf² = 18.49 - 5

Vf² = 13.49

using the square root, we have.

Vf = 3.67 [m/s]

8 0
2 years ago
What is work please give ans​
Fed [463]
Work= force x displacement :)
8 0
2 years ago
If the bond enthalpy for a C-H bond is 413 kJ, what will happen when the C-H bond is broken?
pentagon [3]

Explanation:

Bond Enthalpy : It is defined as amount of energy required to break a the particular bond in there gaseous state. It is also known as bond energy. It units are kJ/mol.

  • Breaking of a bond is an Endothermic process (energy absorbed from the surroundings).
  • Formation of bond is an Exothermic process (energy is released to the surroundings).

If the average bond enthalpy for a C-H bond is 413 kJ/mol, When the C-H bond breaks in which energy will be required ,which will be an endothermic reaction.

8 0
3 years ago
15) What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of .35 m?
____ [38]

A pendulum is not a wave.

-- A pendulum doesn't have a 'wavelength'.

-- There's no way to define how many of its "waves" pass a point
every second.

--  Whatever you say is the speed of the pendulum, that speed
can only be true at one or two points in the pendulum's swing,
and it's different everywhere else in the swing.

-- The frequency of a pendulum depends only on the length
of the string from which it hangs.


If you take the given information and try to apply wave motion to it:

             Wave speed = (wavelength) x (frequency)

             Frequency  =  (speed) / (wavelength) ,

you would end up with

             Frequency = (30 meter/sec) / (0.35 meter) = 85.7 Hz

Have you ever seen anything that could be described as
a pendulum, swinging or even wiggling back and forth
85 times every second ? ! ?     That's pretty absurd. 

This math is not applicable to the pendulum.

6 0
3 years ago
From this diagram which of the following can you conclude
Volgvan

Answer: A

Explanation:

I say opposites attract

3 0
3 years ago
Read 2 more answers
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