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Maslowich
3 years ago
14

Under which condition would time periods of daylight and darkness be equal everywhere on Earth all year? A. if Earth revolved ar

ound the sun in a more circular orbit B. if Earth rotated on an axis that was not tilted with respect to Earth's orbit C. if Earth had two moons D. if Earth revolved in an orbit closer to the sun
Physics
2 answers:
FromTheMoon [43]3 years ago
8 0
The answer is b because that is the correct one
Alecsey [184]3 years ago
3 0
I guess it is B as it is more relevant to reality and also the duration of the day is independent off the others.
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A rocket is launched upward with a constant acceleration of 165 m/s^2. After 8.00 seconds of ascension a passenger on the rocket
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To solve this problem we will apply the concepts related to the linear kinematic movement. We will start by finding the speed of the body from time and the acceleration given.

Through the position equations we will calculate the distance traveled.

Finally, using this same position relationship and considering the previously found speed, we can determine the time to reach your goal.

For time (t) and acceleration (a) we have to,

t = 8s, a = 165m/s^2

The velocity would be,

u = a*t \\u = 165*8\\u = 1320m/s

Now the position is,

h= \frac{1}{2} at^2

h = \frac{1}{2} 165*8^2

h = 5280m

Now with the initial speed and position found we will have the time is,

h=ut +\frac{1}{2} at^2

-5280=1320t - \frac{1}{2} 9.8t^2

4.9t^2-1320t-5280=0

Solving the polynomian we have,

t = 273.33s = 4.56minutes

Therefore  the rocket will take to hit the ground around to 4.56min

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Bezzdna [24]
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Arysha enjoys playing lacrosse on the school team. Suppose Arysha throws a lacrosse ball with a force of 6 N, and the resulting
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Explanation:

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Mass = \frac{6N}{43m/s^2}

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Answer:

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