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3 years ago

Solve a/3 + 4 = 6 a=

Mathematics

2 answers:

Andru [333]3 years ago

7 0

Answer:

a = 6

Step-by-step explanation:

Given

$\frac{a}{3}$ + 4 = 6 ( subtract 4 from both sides )

$\frac{a}{3}$ = 2 ( multiply both sides by 3 to clear the fraction )

a = 6

STatiana [176]3 years ago

4 0

Answer:

a=6

Step-by-step explanation:

a/3=6-4

a/3=2

a=6

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Graph the linear equation using intercepts. Use a graphing calculator to check your graph.

Gekata [30.6K]

Answer:

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Step-by-step explanation:

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2 years ago

50 POINTS WILL GIVE BRAINIEST. Which of the following numbers are irrational?

Otrada [13]

Answer:

$\sf \dfrac{\pi}{3}\:\:and\:\:\sqrt[\sf 3]{\sf 25}$

Step-by-step explanation:

Definitions

Integer: A whole number that can be positive, negative, or zero.

Rational Number: A number that can be expressed as the ratio of two integers (where the denominator does not equal zero).

Irrational Number: A real number that cannot be written as a rational number.

$\sf -8.2183 \times 10000=-82183$

$\implies \sf -8.2183=-\dfrac{82183}{10000}$

Therefore, -8.2183 can be expressed as a rational number.

π is an infinite decimal, so it cannot be expressed as a rational number.

$\textsf{Therefore},\:\dfrac{\pi}{3}\:\textsf{is irrational}.$

$\sqrt[\sf 3]{\sf 25}$ is an irrational number.

$\sf 9+ \sqrt{4}=9+\sqrt{2^2}=9+2=11$

As 11 can be expressed as ¹¹/₁ then 9 + √4 is rational.

Conclusion

Therefore, the numbers that are irrational are:

$\sf \dfrac{\pi}{3}\:\:and\:\:\sqrt[\sf 3]{\sf 25}$

8 0

1 year ago

Two complex numbers are represented by c + di and , where c, d, e, and f are positive real numbers. In what two quadrants may th

myrzilka [38]

Answer: In quadrant 1 or quadrant 2.

Step-by-step explanation:

We have the numbers:

x = c + di

y = e + fi

where c, d, e and f are real positive numbers.

the product of these numbers is:

x*y = (c + di)*(e + fi) = c*e + c*fi + d*ei ´+d*f*i^2

x*y = c*e - d*f + (c*f + d*e)i

where I used that i^2 = -1

knowing that c,f, d and e are positive numbers, then the imaginary part of the product must be always positive.

For the real part, we have c*e - d*f, that can be positive o negative depending on the values of c, e, d, and f.

So we have that the product must lie always in one of the upper two quadrants, quadrant 1 or quadrant 2 because the imaginary part is always positive and the real part can be positive or negative.

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3 years ago

If 2x + 3z = 12, and z = -2, then x=6 true or false

zalisa [80]

2x + 3z = 12 and z = -2, then x=6

2x + 3(-2) = 12
2x = 18
x = 9

answer

False

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3 years ago

Need help with this question

Sedbober [7]

Answer:

Step-by-step explanation:

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3 years ago