Tell me please I need help with this one guys pleaseee thanks you so much :()))

Riley and Rhoda plan to buy 2 bags of dog of food and a dog collar (x). Each bag of dog food costs $7 and the dog collar costs $

Sergio [31]

Let:

T = Total money they have

Dc = Dog collar

x = Number of bags of food

$\begin{gathered} 2x+Dc\le T \\ 2x+4.5\le30 \end{gathered}$

Let's solve the inequality:

$\begin{gathered} 2x+4.5\le30 \\ \text{subtract 4.5 from both sides:} \\ 2x+4.5-4.5\le30-4.5 \\ 2x\le25.5 \\ x\le\frac{25.5}{2} \\ x=12.75\approx12 \end{gathered}$

This means that they can buy 12 bags of food at most.

Since they plan to buy 2 bags of food:

$\begin{gathered} 2(7)+4.5\le30 \\ 14+4.5\le30 \\ 18.5\le30 \end{gathered}$

This means they can do it and have $ 11.5 to spare

7 0

1 year ago

On which number do i put a vinculum line on 0.166666667?I WILL PUT BRAINLIST if it's useful

MAVERICK [17]

Answer:

On 6

Step-by-step explanation:

On 6 to show that it continues

6 0

4 years ago

Two surfers and statistics students collected data on the number of days on which surfers surfed in the last month for 30 longbo

Alisiya [41]

Answer:

Do not reject H0. The mean days surfed for longboarders is significantly larger than the mean days surfed for all shortboarders

Step-by-step explanation:

The null hypothesis is that the mean days surfed for all long boarders is larger than the mean days surfed for all short boarders

H0: μL > μs against the claim Ha: μL≤ μs

the alternate hypothesis is the mean days surfed for all long boarders isless or equal to the mean days surfed for all short boarders (because long boards can go out in many different surfing conditions)

The test statistic is

t= x1- x2/ √s1/n1+ s2/n2

1) Calculations

Longboards

Mean

ˉx=∑x/n=4+8+9+4+9+7+9+6+6+11+15+13+16+12+10+12+18+20+15+10+15+19+21+9+22+19+23+13+12+10/30

=377/30

=12.5667

Longboard Variance S2=[∑dx²-(∑dx)²/n]/n-1

=[831-(-13)²/30]/29

=831-5.6333/29

=825.3667/29

=28.4609

Shortboard Mean

ˉx=∑x/n=6+4+6+6+7+7+7+10+4+6+7+5+8+9+4+15+13+9+12+11+12+13+9+11+13+15+9+19+20+11/30

=288/30

=9.6

Shortboard Variance S2=[∑x²-(∑x)²/n]/n-1

=[ 3270-(288)2/30]/29

=3270-2764.8/29

=505.2/29

=17.4207

2) Putting values in the test statistic

t=|x1-x2|/√S²1/n1+S²2/n2

t =|12.5667-9.6|/√28.4609/30+17.4207/30

t =|2.9667|/√0.9487+0.5807

t=|2.9667|/√1.5294

t=|2.9667|/1.2367

t=2.3989

3) Degree of freedom =n1+n2-2=30+30-2=58

4) The critical region is t ≤ t(0.05) (58) =1.6716

5) Since the calculated t= 2.4 does not fall in the critical region t(0.05) (58) ≤ 1.6716 we do not reject H0.

The p-value is 0.008969. The result is significant at p <0 .05.

6 0

3 years ago

Bryan and Jadyn had barbeque potato chips and soda at a football party. Bryan ate 3 oz of chips and drank 2 cups of soda for a t

Diano4ka-milaya [45]

Answer:

200 mg sodium is in 1 oz of chips and 50 mg sodium is in 1 cup of soda.

Step-by-step explanation:

Let x mg sodium is in 1 oz of chips and and y mg is in 1 cup of soda.

∵ Bryan ate 3 oz of chips and drank 2 cups of soda for a total of 700 mg of sodium.

i.e. 3x + 2y = 700 --------(1),

Jadyn ate 1 oz of chips and drank 3 cups of soda for a total of 350 mg of sodium.

i.e. x + 3y = 350 ---------(2),

Equation (1) - 3 × equation (2),

We get,

2y - 9y = 700 - 1050

-7y = -350

$\implies y = \frac{-350}{-7}= 50$

From equation (1),

3x + 2(50) = 700

3x + 100 = 700

3x = 700 - 100

3x = 600

$\implies x = \frac{600}{3}=200$

Hence, 200 mg sodium is in 1 oz of chips and 50 mg sodium is in 1 cup of soda.

7 0

4 years ago

SOMEONE HELP ME ON THESE QUESTIONS

dem82 [27]

1.) The sum(addition) of 21 and 5 times(multiplication) a number f is(=) 61.

f = unknown number/variable [So 21 plus 5f(5 times f) equals 61]

21 + 5f = 61 [21(one-time) + 5f(number x variable) = 61(total)]

2.) Seventeen more(addition) than seven times(multiplication) a number j is(=) 87.

j = unknown number/variable [So 17 plus 7j(7 times j) equals 87]

17 + 7j = 87

3.) n = number of calls

18 + 0.05n = 50.50

[Company charges $18 plus five cents per call(n), and the total charge was $50.50]

4.) s = the number of students

40 + 30s = 220

[Tutor charges $40 plus $30 per student(s), and the total charge was $220]

4 0

3 years ago