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TEA [102]
3 years ago
7

Consider a voltaic cell constructed with a silver electrode placed in a 1.0 M AgNO3 solution and an aluminum electrode placed in

a 1.0 M Al(NO3)3 solution. Write out the half reactions that occur at the anode and the cathode (4 points). Determine the cell potential and the direction of electron flow
Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
8 0

Answer:

2.46V

Explanation:

Oxidation half equation

Al(s)------> Al^3+(aq) + 3e

Reduction half equation

3Ag^+(aq) +3e --------> 3Ag(s)

Since the concentration of each solution is 1M we assume standard conditions

E°cell = E°cathode - E°anode

E°cathode= 0.80V

E°anode= -1.66V

E°cell = 0.80 - (-1.66)

E°cell = 2.46V

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When hydrochloric acid and zinc were combined, the flask was sealed and thus no gas could escape from the flask. why did the pre
JulijaS [17]
When hydrochloric acid and zinc were combined, the salt zinc chloride and hydroge gas are being produced in the flask. The flask was said to be sealed and, therefore, no gas could escape from the flask. As the temperature decreases, the pressure inside would decrease since the gas would have lower kinetic energy and would have less force to exert on the walls of the flask. This is also evident from the equation PV = nRT. As we can see pressure and temperature are directly related which means as one decreases, the other decreases as well or as one increases, the other would increase accordingly.
7 0
4 years ago
Read 2 more answers
CdF2(s)⇄Cd2+(aq)+2F−(aq)A saturated aqueous solution of CdF2 is prepared. The equilibrium in the solution is represented above.
kupik [55]

Answer:

The correct answer is option a.

Explanation:

CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)

Equilibrium concentration cadmium ions = [Cd^{2+}]=0.0585 M

Equilibrium concentration fluoride ions = [F^{-}]=0.117 M

Molar solubility is the maximum concentration of salt present in water in ionic form beyond that no more salt will exist in its ionic form and will settle down in bottom of the solution.

The molar solubility of the solid cadmium fluoride = 0.0585 M

CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)..[1]

NaF(s)\rightleftharpoons Na^{+}(aq)+F^-(aq)

Due to addition of sodium fluoride will increase concentration of fluoride in the solution.And due to common ion effect the equilibrium will shift in backward direction in [1], that is precipitation of more cadmium fluoride.

Hence, decrease in solubility will be observed.

8 0
3 years ago
How many moles of NH3 can be made from 0.93 moles N2?
STALIN [3.7K]
I think the answer is D
7 0
3 years ago
Why does a substances density decrease as it heats up
mariarad [96]

Answer:

Heating a certain substance causes molecules to speed up and spread slightly further apart, having a larger volume that results in a decrease in the density. Cooling a substance causes molecules to slow down and get closer together, occupying a smaller volume that results in the increase in density.

Explanation:

7 0
3 years ago
Explain how steam causes burns by describing the transfer of heat.
erica [24]

Answer:

It will be : (in simple terms)

Condensation of hot steam or hot vapor on the cooler skin releases the water's latent heat of vaporization, rapidly raising the temperature of the skin which will result in steam burns.

Hope it helped

All the best!!

8 0
3 years ago
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