I will not stop asking until someone answer hurry up already

Dustin is mixing concrete. A formula for concrete calls for 3/8 gal of water. Dustin wants to make 7/9 more concrete than the fo

slava [35]

We can use a ratio to solve this question. Lets refer to the amount formed by the formula as a serving
1 serving needs 3/8 gal
We want to create 7/9 servings extra, so
1 + 7/9 = 16/7
1 : 3/8
16/7 : x
1/(3/8) = (16/7) / x
8 / 3 = 16x / 7
x = 7/6
He needs to use 7/6 gallons of water.

5 0

3 years ago

How many atoms do I have if I have 2 moles of Hydrogen atoms?

maw [93]

Answer: 6

Explanation: if you multiply the number of moles in the hydrogen atoms by the number of the once displayed and you multiply it by 3 and get the answer 6

6 0

3 years ago

The rock in a particular iron ore deposit contains 78% Fe2O3 by mass. How many kilograms of the rock must a mining company proce

Studentka2010 [4]

Answer:

103 so easy so free dogwater

Explanation:

6 0

3 years ago

What product is formed when benzene reacts with isobutyl chloride in the presence of AlCl3?

oee [108]

The product formed when benzene reacts with isobutyl chloride in the presence of AlCl3 is tertiary butyl benzene.

THE CHEMICAL REACTION AS

step 1 : CH₃ - CH - CH₂Cl + AlCl₃ → CH₃ - CH₂ -CH₂ - CH₂⁺ + AlCl⁻

step 2: CH₃ - CH₂ - CH₂ - CH₂⁺ ---H SHIFT--→ (CH₃)₃C⁺

PRODUCT

C₆H₆ + (CH₃)₃ C⁺ → C₆H₆ ( CH₃)₃ C⁺

Hence the product formed is tertiary butyl benzene.

Learn more about chemical reaction on

brainly.com/question/11231920

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4 0

2 years ago

A student determines the aluminum content of a solution by first precipitating it as aluminum hydroxide, and then decomposing th

Vladimir [108]

Answer: The student should obtain <u>1.103 g of aluminum oxide </u>

Explanation:

First we write down the equations that represent the aluminum hydroxide precipitation from the reaction between the aluminum nitrate and the sodium hydroxide:

Al(NO3)3 + 3NaOH → 3NaNO3 + Al(OH)3

Now, the equation that represents the decomposition of the hydroxide to aluminum oxide by heating it.

2Al(OH)3 → Al2O3 + 3H2O

Second, we gather the information what we are going to use in our calculations.

Volumen of Al(NO3)3 = 40mL

Molar concentration of Al(NO3)3 = 0.541M

Molecular Weight Al2O3 = 101.96 g/mol

Third, we start using the molar concentration of the aluminum nitrate and volume used to find out the total amount of moles that are reacting

$\frac{0.541moles Al(NO3)3}{1L} x\frac{1L}{1000mL} x 40mL Al(NO3)3 = 0.022moles Al(NO3)3$

then we use the molar coefficients from the equations to discover the amount of Al2O3 moles produced

$0.022moles Al(NO3)3 x \frac{1mol Al(OH)3}{1mol Al(NO3)3} X\frac{1mol Al2O3}{2molAl(OH)3} = 0.011 moles Al2O3$

finally, we use the molecular weight of the Al2O3 to calculate the final mass produced.

$0.011moles Al2O3 x \frac{101.96g Al2O3}{1mol Al2O3} = 1.103g Al2O3$

4 0

4 years ago