Answer:
Final temperature = ![43.53^{\circ} C](https://tex.z-dn.net/?f=43.53%5E%7B%5Ccirc%7D%20C)
Explanation:
Given that,
Heat added, Q = 250 J
Mass, m = 30 g
Initial temperature, T₁ = 22°C
The Specific heat of Cu= 0.387 J/g °C
We know that, heat added due to the change in temperature is given by :
![Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20T%5C%5C%5C%5CQ%3Dmc%28T_2-T_1%29%5C%5C%5C%5C%5Cdfrac%7BQ%7D%7Bmc%7D%3D%28T_2-T_1%29%5C%5C%5C%5CT_2%3D%5Cdfrac%7BQ%7D%7Bmc%7D%2BT_1)
Put all the values,
![T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C](https://tex.z-dn.net/?f=T_2%3D%5Cdfrac%7B250%7D%7B30%5Ctimes%200.387%7D%2B22%5C%5C%5C%5C%3D43.53%5E%7B%5Ccirc%7D%20C)
So, the final temperature is equal to
.
Thomson's model of the atom was called the plum pudding model. He discovered electrons, so he placed them in the atoms. This was before the nucleus was discovered.
Now, the current model is an atom that contains a positively charged nucleus (with both protons and neutrons), and negatively charged orbitals with electrons.
Answer:
a. 2.44 nm
b. 15.33 nm²
Explanation:
a. Calculate the thickness (in nm) of the surface film
Since the volume of a teaspoon equals V = 4.93 cm³ and the area of the oil film is half an acre = 1/2 × 4046.86 m² = 2023.43 m²
The volume of the oil film, V' equals the volume of the oil in the teaspoon, V
V' = Ah where A = cross-sectional area of oil film = 2023.43 m² = 2023.43 × 10⁴ cm² and h = height of oil film
So, V' = V
Ah = V
h = V/A
= 4.93 cm³/2023.43 × 10⁴ cm²
= 0.00244 × 10⁻⁴ cm
= 2.44 × 10⁻⁷ cm
= 2.44 × 10⁻⁷ cm × 1m/100 cm
= 2.44 × 10⁻⁹ m
= 2.44 nm
b. The surface area (in nm2) occupied by an oleic acid molecule on water.
Since the height of the oil film equals the diameter of the oil molecule, and the molecule is assumed to be a sphere of radius, r. Its surface area is thus A = 4πr²
r = h/2 = 2.44 nm/2 = 1.22 nm
A = 4πr²
A = 4π(1.22 nm)²
A = 4.88π nm²
A = 15.33 nm²