Answer:
18
Step-by-step explanation:
I did that in my head could be wrong
12>x-5 is the answer your looking for. Make sure to put a line under the more than sign, my computer wouldn't allow me to plug that part in.
Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
Answer:
Depending on how the input of each function defined,
- The first choice
, - The third choice
- The fourth choice
might be functions.
Step-by-step explanation:
A function between two sets (domain and range) should
- be defined for all elements in the domain, and
- map each element from the domain to exactly one element in the range.
The second choice can't be a function since the element 
from the domain is mapped to more than one element in the range.
Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be 
. Similarly, the domain for the third and fourth relations should be 
and 
Answer:
Please provide the statements.
Step-by-step explanation:
